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Anon25 [30]
3 years ago
6

An orange has about 1/4 cup of juice. How many oranges are needed to make 2 1/2 cups of juice? Select all equations that represe

nt this question. Plz answer!

Mathematics
2 answers:
san4es73 [151]3 years ago
7 0
A and D are correct. To understand this, you need to know that this scenario gives us a total (2 1/2 cups) and a part (1/4). When you have these 2 pieces of information you have either a division problem with a total divided into parts (choice D) or you have one part and a totol shown as a multiplication problem (choice A).
Scilla [17]3 years ago
4 0

Answer:

The answer is

D (2 1/2)/(1/4)

And 10

Oranges are needed to make 2 1/2 cups of juice

Step-by-step explanation:

From the given expression

We can solve the problem

If we state it out Mathematically

Step one

1 orange will give 1/4 cup of juice

x orange will give 2 1/2 cups of juice

Step two

By cross multiplication we have

x=( 2 1/2)/(1/4)

Let's convert the mixed fraction

2 1/2

to proper fraction we have 5/2

x=( 5/2)/(1/4)

x=5/2*4/1

x=20/2

x=10

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A desk is 39 inches wide. What is the width in yards
Stolb23 [73]

Answer:

1.0833 yd

Step-by-step explanation:

Inches    Yards

37"         1.0278 yd

38"         1.0556 yd

39"         1.0833 yd

40"         1.1111 yd

Have a great day! :D

4 0
2 years ago
Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your
BaLLatris [955]

f(x,y)=\dfrac{y^3}x

a. The gradient is

\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath

\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}

b. The gradient at point P(1, 2) is

\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}

c. The derivative of f at P in the direction of \vec u is

D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}

It looks like

\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath

so that

\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2

Then

D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}

\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}

7 0
3 years ago
Plzzz help asapppppp what is the inverse of f if f(x)=^3 sqrt x-5
jasenka [17]

Hello from MrBillDoesMath!

Answer:

The first choice, y = x^3 + 5


Discussion:

Let

y = (x-5) ^ (1/3)

To find the inverse, sway x and y and then solve for y:

x = ( y - 5 )^(1/3)         =>             cube both sides

x^3 = y - 5                  =>             add 5 to both sides

x^3 + 5 = y


So the inverse is  x^3 + 5, which is the first choice


Thank you,

MrB

4 0
3 years ago
Read 2 more answers
0.0000056 rewritten as a single digit<br> times a power of ten becomes:
Masteriza [31]

Answer:

5.6× 10^ -6

.......................

3 0
3 years ago
Change the decimal into a %:0.7
Tomtit [17]
Simply multiply 0.7 by 100. 0.7 x 100= 70%. The answer is 70%
8 0
3 years ago
Read 2 more answers
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