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FrozenT [24]
3 years ago
9

So yeah. . .. idk how to do this

Mathematics
1 answer:
kipiarov [429]3 years ago
5 0

<em>Please </em>use for reference. Merci.

To find rate of change simply divide y/x.

hour 2: 56/2=28

hour 4: 125/4~about 31.3 or 31

hour 5: 164/5=32.8 or ~ 33

hour 8: 271/8 ~ about 34 or 33.875

hour 13: 404/13 ~ about 31 or 31.0769231

What numbers are the largest?

hours 5 and 8

Thus, the correct answer was option C.

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10 to the second power+6.7+8
svp [43]

Question

10 to the second power+6.7+8


Answer:

<h2>114.7</h2>

Step-by-step explanation:


10² + 6.7 + 8 =

100 + 6.7 + 8 =

114.7



7 0
3 years ago
Is the sqrt of 1 - sin^2 theta = cos theta true? If so, in which quadrants does angle theta terminate?
Genrish500 [490]

Answer:

Answer: The answer is option B.

Step-by-step explanation:

Here,

We have,

{ \sin }^{2}  theta \: +  {cos}^{2}theta  = 1

{cos}^{2} \: theta  = 1 -  {sin}^{2}  \: theta

cos \: theta =  \sqrt{1 -  { \sin }^{2}theta }

So, it's true; and it lies in quadrant 1 and 4.

The reason according to the "CAST" rule cos theta is in 1st and 3rd quadrant cos theta is positive.

7 0
3 years ago
4m≥m+9&gt;-9+4m<br> Please answer urgent
Vsevolod [243]
Next time, please include the instructions.

This inequality could be broken into two parts:

4m\geq m + 9   AND   m + 9 > -9 + 4m

Focus first on the inequality m + 9 > -9 + 4m.  subtract m from both sides, obtaining:

9 > -9 + 3m.  Next, add 9 to both sides, obtaining:  18>3m, or m<6

Last step:  Determine whether the inequality <span>4m≥m+9 is true if m<6.</span>
5 0
3 years ago
The Converse of the Pythagorean says that if a²+b²=c²the triangle is a right triangle. Use the Converse of the Pythagorean Theor
mina [271]
A is the answer to your question
5 0
2 years ago
Read 2 more answers
A) Dos números enteros positivos se diferencian en 6 unidades y la suma de sus cuadrados
lianna [129]

Queremos encontrar dos números enteros tales que su diferencia sea de 6 y la suma de sus cuadrados sea igual a 260.

Veremos que los dos números son 8 y 14.

Primero, podemos definir esos números como A y B.

Entonces tenemos que:

A - B = 6

A^2 + B^2 = 260

Esto es un sistema de ecuaciones.

Para resolverlo, el primer paso es aislar una de las variables en una de las ecuaciones, vamos a hacer esto en la primera.

A - B = 6

A = 6 + B

Ahora reemplazamos esto en la otra ecuación.

A^2 + B^2 = 260

(6 + B)^2 + B^2 = 260

36 + 12*B + B^2 + B^2 = 260

36 + 12*B + 2*B^2 = 260

Ahora podemos resolver esto para B:

2*B^2 + 12*B + 36 - 260 = 0

2*B^2 + 12*B - 224

Las soluciones estan dadas por la formula de Bhaskara:

B = \frac{-12\pm \sqrt{12^2 - 4*2*(-224)} }{2*2} \\\\B =  \frac{-12 \pm 44 }{4}\\\\B =  (-3 \pm 11)

Entonces las dos soluciones son:

B = -3 + 11 = 8

B = -3 - 11 = -14

Sabemos que los números son positivos, asi que elejimos la primera, entonces tenemos:

B = 8.

Con esto podemos calcular el valor de A como:

A - B = 6

A = 6 + B = 6 + 8 = 14

Entonces los dos números son:

8 y 14.

Si deseas aprender más, puedes leer:

brainly.com/question/24761554

6 0
2 years ago
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