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The value of f(5) is 49.1
Step-by-step explanation:
To find f(x) from f'(x) use the integration
f(x) = ∫ f'(x)
1. Find The integration of f'(x) with the constant term
2. Substitute x by 1 and f(x) by π to find the constant term
3. Write the differential function f(x) and substitute x by 5 to find f(5)
∵ f'(x) = + 6
- Change the root to fraction power
∵ =
∴ f'(x) = + 6
∴ f(x) = ∫ + 6
- In integration add the power by 1 and divide the coefficient by the
new power and insert x with the constant term
∴ f(x) = + 6x + c
- c is the constant of integration
∵
∴ f(x) = + 6x + c
- To find c substitute x by 1 and f(x) by π
∴ π = + 6(1) + c
∴ π = + 6 + c
∴ π = 6.4 + c
- Subtract 6.4 from both sides
∴ c = - 3.2584
∴ f(x) = + 6x - 3.2584
To find f(5) Substitute x by 5
∵ x = 5
∴ f(5) = + 6(5) - 3.2584
∴ f(5) = 49.1
Answer:
A) 44.1
Step-by-step explanation:
I used omnicalculator. Should count because it's still a calculator.
Answer:
x = 15.49
Step-by-step explanation:
a2+b2=c2
11^2+x^2=19^2
121 =x^2 = 361
x^2 = 240
x = 15.49
Simplify √-y to √yi
3+ 2y = √yi
Square bot sides
(3 + 2y)^2 = -y
Expand
9 + 12y + 4y^2 = -y
Move all terms to one side
9 + 12y + 4y^2 + y = 0
Simplify 9 + 12y + 4y^2 + y to 9 + 13y + 4y^2
9 + 13y + 4y^2 = 0
Split the second term in 9 + 13y + 4y^2 into two terms
4y^2 + 9y + 4y + 9 = 0
Factor out common terms in the first two terms, then in the last two terms
y(4y + 9) + (4y + 9) = 0
Factor out the common term 4y + 9
(4y + 9)(y + 1) = 0
Solve for y
y = -9/4, -1
Check solution
when y = -9/4, the original equation; 3 + 2y = √-y does not hold true. We will drop y = -9/4 from the solution set.
Therefore,
<u>y = -1</u>
