Answer:
yessir it is
Step-by-step explanation:
Given:
Hyperbola
a=55,000 km and c=81,000 km
hyperbola is the origin and the
transverse axis is horizontal
Required:
Equation of the path of a
satellite
Solution:
Formula for hyperbola, (x-h)2/a2
– (x-k)2/b2 = 1
At origin, (h, k) = (0, 0)
(x-0)2/(55000)2 – (x-0)2/(81000)2
= 1
<span>X2/12100 – y2/26244 = 250000</span>
First step you should do is s<span>implify both sides of your equation:
</span>29-(x+8)=6x-7
Distribute the Negative Sign:
29+-1(x+8)=6x-7
29+-1x+(-1)(8)=6x-7
29+-x+-8=6x-7
29+-x+-8=6x+-7
<span>Combine Like Terms:
</span>(-x)+(29+-8)=6x-7
-x+21=6x-7
<span>Subtract 6x from both sides:
</span>-x+21-6x=6x-7-6x
-7x+21=-7
<span>Subtract 21 from both sides:
</span>-7x+21-21=-7-21
-7x=-28
<span>Divide both sides by -7:
</span>-7x/-7 = -28/-7
And now your answer should be:
x=4
~~~~~
Good luck~ Sans
Answer:
6
Step-by-step explanation:
2 halves make a whole so multiply 2 by 3. the answer is six. you can also add the halves. 1/2+1/2+1/2+1/2+1/2+1/2=3.
Answer:
Part 1) m∠EFG=94°
Part 2) m∠GFH=86°
Step-by-step explanation:
we know that
m∠EFG+m∠GFH=180° -----> by linear pair (given problem)
we have
m∠EFG=3n+22
m∠GFH=2n+38
substitute the values
(3n+22)°+(2n+38)°=180°
Solve for n
(5n+60)=180
5n=180-60
5n=120
n=24
<em>Find the measure of angle EFG</em>
m∠EFG=3n+22
substitute the value of n
m∠EFG=3(24)+22=94°
<em>Find the measure of angle GFH</em>
m∠GFH=2n+38
substitute the value of n
m∠GFH=2(24)+38=86°
