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Tanya [424]
3 years ago
6

Please help me answer this question in the picture.

Mathematics
2 answers:
Yanka [14]3 years ago
7 0
The awnser is B because It has more X marks 
Tems11 [23]3 years ago
6 0
I did this in third grade. I don't renember much but I'm pretty sure its A 1/8
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Which situation could this graph represent?
HACTEHA [7]

Situation: The answer is D because running up a hill first takes less time, which you can see in the graph. Then, walking up a hill takes more time and you are going upward, which is expressed in the graph. Next, you run down the hill, which takes less time than walking which is on the graph. Finally, you walk the remainder of the hill downwards, which takes more time and is shown in the graph. Hope this helps!

7 0
2 years ago
Read 2 more answers
Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the eq
lawyer [7]

Answer:

The value of rate of decrease of volume = - 3600 \frac{k pa}{min}

Step-by-step explanation:

According to Boyle's law P V = C ------- (1)

Pressure ( P ) = 100 k pa = 10 \frac{N}{cm^{2} }

Volume ( V ) = 900 cm^{3}

Put these values in equation ( 1 ) we get,

⇒ C = 10 × 900 = 9000 N-cm = 90 N-m

Differentiate Equation ( 1 ) with respect to time we get,

⇒ V \frac{dP}{dt} + P \frac{dV}{dt} = 0

⇒ V \frac{dP}{dt} = - P \frac{dV}{dt}

⇒ \frac{dV}{dt} = - \frac{V}{P} \frac{dP}{dt} ---------- (2)

This equation gives the rate of decrease of volume.

Given that Rate of increase of pressure = \frac{dP}{dt} = 40 \frac{k pa}{min}

C = 90 N-m

P =  10^{5} pa = 10 \frac{N}{cm^{2} }

V = 900 cm^{3}

Put all the above values in equation 2 we get,

⇒  \frac{dV}{dt} = - \frac{900}{10} × 40

⇒  \frac{dV}{dt} = - 3600 \frac{k pa}{min}

This is the value of rate of decrease of volume.

8 0
3 years ago
amanda ran 4 laps around the school track. Clifford ran half as many laps as brian ran. Together the 3 friends ran 13 laps. How
Mariulka [41]

Answer: 6 laps

Step-by-step explanation:

13  - 4= 9 left  6 and half would be three

7 0
3 years ago
PLEASE PLEAE PLEASE HELP
scoundrel [369]
She bought 4 coffees! :)
7 0
3 years ago
Let x and y be independent each uniformly distributed on {1,2,...,n} find p(x < y )
bulgar [2K]
If we draw the contingency table of x (vertical) against y (horiz.), we have a square.
For n=4, we have   (legend:  < : x<y   = : x=y   > : x>y

y      1  2  3  4
x
1      = <  <  <
2      > =  <  < 
3      >  >  = <
4      >  >  >  =

We see that there are n(n-1)/2 cases of x<y out of n^2.
Therefore, 
p(x<y)=n(n-1)/(2n^2)=(n-1)/(2n)

However, if the sample space is continuous, it will be simply p(x<y)=1/2.

8 0
3 years ago
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