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2 years ago

Han is solving an equation. He took steps that are acceptable but ended up with equations that are clearly not true.

Mathematics

1 answer:

borishaifa [10]2 years ago

4 0

Answer:

no solution

Step-by-step explanation:

5x+6=7x+5-2x original equation

5x+6=7x-2x+5 apply the commutative property

5x+6=5x+5 combine like terms

6=5subtract 5x from each side

Since this is never true, there is no solution

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What is the slope formula of (-9,15) and (-9,-8) ?

skad [1K]

Answer:

m = undefined

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Slope Formula: $\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (-9, 15)

Point (-9, -8)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Substitute in points [SF]: $\displaystyle m=\frac{-8-15}{-9+9}$
[Fraction] Subtract/Add: $\displaystyle m=\frac{-23}{0}$

Here we see that our slope would be undefined since we cannot divide anything by 0.

5 0

3 years ago

A small plane and a large plane are 6.8km from each other, at the same altitude (height). From an observation tower, the two air

Lemur [1.5K]

Answer:

7.9km

Step-by-step explanation:

(a)See attached for the diagram representing this situation.

(b)

In Triangle ABC

$\text{Using Law of Sines}\\\dfrac{\sin A}{a}=\dfrac{\sin C}{c} \\\dfrac{\sin A}{5.2}=\dfrac{\sin 58^\circ}{6.8} \\\sin A=5.2 \times \dfrac{\sin 58^\circ}{6.8}\\A=\arcsin (5.2 \times \dfrac{\sin 58^\circ}{6.8})\\A=40.43^\circ$

Next, we determine the value of Angle B.

$\angle A+\angle B+\angle C=180^\circ\\40.43+58+\angle B=180^\circ\\\angle B=180^\circ-(40.43+58)\\\angle B=81.57^\circ$

Finally, we find b.

$\text{Using Law of SInes}\\\dfrac{b}{\sin B}=\dfrac{c}{\sin C} \\\dfrac{b}{\sin 81.57^\circ}=\dfrac{6.8}{\sin 58^\circ} \\b=\dfrac{6.8}{\sin 58^\circ} \times \sin 81.57^\circ\\b=7.9km $ (to the nearest tenth of a kilometer)$

The distance between the small plane and the observation tower is 7.9km.

8 0

3 years ago

Solve. 12 – (2 × 3) A. 6 B. 12 C. 12(2) D. 23

atroni [7]

$12-\bigg(2*3\bigg) \\ \\ 12 -6 \\ \\ \boxed{\boxed{\boxed{\pmb{=6}}}}$

4 0

3 years ago

Find the rationalizing factor of:

nataly862011 [7]

Answer:

Check out the answer. Hope it helps!!

8 0

2 years ago

Distance on graph

Mnenie [13.5K]

The graph can be divided into two shapes. A rectangle and a right triangle.

The distance that the rover will cover if it completes one circuit can be computed using the Pythagorean theorem and adding the sides of the rectangle.

Rectangle:
Width = 4 - 2 = 2 meters
Length = 11 - 2 = 9 meters

Triangle = 16 - 2 = 14 ; 14 - 2 = 12 meters (this is the short leg)
long leg of the triangle = length of the rectangle = 9 meters.

12² + 9² = c²
144 + 81 = c²
225 = c²
√225 = √c²
15 = c

Point A to B = 4 - 2 = 2 meters
Point B to C = 15 meters
Point C to D = 16 - 2 = 14 meters
Point D to A = 11 - 2 = 9 meters

Total distance traveled = 2 + 15 + 14 + 9 = 40 meters.

6 0

2 years ago