Just give similar examples with different number value.
Answer:
Well If there are answer choices please place them in the comments. But if there are not, that's okay. I'd say that you'd just keep it at 5,900 if you are trying to round to the nearest hundred. If you are trying to round to the nearest thousand, 6,000 would be right.
Remember, if the number is or is between 1 and 5 round down but if it is or is between 5 and 9, round up.
Step-by-step explanation:
Answer:
90 mi/h
Step-by-step explanation:
Given,
For first 30 miles, her speed is 30 miles per hour,
Let x be her speed in miles per hour for another 30 miles,
Since, here the distance are equal in each interval,
So, the average speed of the entire journey
![=\frac{\text{Average speed for first 30 miles + Average speed for another 30 miles}}{2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Ctext%7BAverage%20speed%20for%20first%2030%20miles%20%2B%20Average%20speed%20for%20another%2030%20miles%7D%7D%7B2%7D)
![=\frac{30+x}{2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B30%2Bx%7D%7B2%7D)
According to the question,
![\frac{30+x}{2}=60](https://tex.z-dn.net/?f=%5Cfrac%7B30%2Bx%7D%7B2%7D%3D60)
![30+x=120](https://tex.z-dn.net/?f=30%2Bx%3D120)
![\implies x = 90](https://tex.z-dn.net/?f=%5Cimplies%20x%20%3D%2090)
Hence, she needs to go 90 miles per hour for remaining 30 miles.
Answer:
Step-by-step explanation:
hello :
look this solution :