Question

Y = −(x + 4)2 − 7 vertex

Answer 1

Answer:

The vertex is $(-4,-7)$

Step-by-step explanation:

The vertex form of a parabola is given by:

$y=a(x-h)^2+k$, where (h,k) is the vertex and $a$ is the leading coefficient.

The given parabola has equation:

$y=-1(x+4)^2-7$

When we compare to the vertex form, we have

$-h=4\implies h=-4$ and $k=-7$.

Therefore the vertex is (-4,-7)

Answer 2

Answer:

The vertex (h,k) is (-4,-7).

Step-by-step explanation:

I assume you are looking for the vertex $y=-4(x+4)^2-7$.

The vertex form of a quadratic is $y=a(x-h)^2+k$ where the vertex is (h,k) and a tells us if the parabola is open down (if a<0) or up (if a>0). a also tells us if it is stretched or compressed.

Anyways if you compare $y=-4(x+4)^2-7$ to $y=a(x-h)^2+k$ , you should see that $a=-4,h=-4,k=-7$.

So the vertex (h,k) is (-4,-7).