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4 years ago

11

Follow the steps to solve this equation. 3(2x + 6) – 4x = 2(5x – 2) + 6 1. Use the distributive property: 6x + 18 – 4x = 10x – 4

+ 6 2. Combine like terms: 2x + 18 = 10x + 2 3. Use the subtraction property of equality: 18 = 8x + 2 4. Use the subtraction property of equality: 16 = 8x 5. Use the division property of equality:

2 answers:

Yuliya22 [10]4 years ago

8 0

Answer:

$x=2$ .

Step-by-step explanation:

We have been given an equation $3(2x+6)-4x=2(5x-2)+6$ . We are supposed to solve our given equation step by step.

Step 1: Use the distributive property.

$3\cdot 2x+3\cdot 6-4x=2\cdot 5x-2\cdot 2+6$

$6x+18-4x=10x-4+6$

Step 2: Combine like terms.

$6x-4x+18=10x-4+6$

$2x+18=10x+2$

Step 3: Use subtraction property of equality:

$2x-2x+18-2=10x-2x+2-2$

$16=8x$

Step 4: Use the division property of equality:

$\frac{16}{8}=\frac{8x}{8}$

$2=x$

Therefore, the solution of our given equation is $x=2$ .

Leokris [45]4 years ago

6 0

Answer:

2

Step-by-step explanation:

test

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In the 1980s an average mortgage rate was around 18.5 how much less per month would a 150000 30 year mortgage by today if the cu

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Answer:

$1516.69 per month less

Step-by-step explanation:

The formula for the monthly payment A on a loan of principal P, annual rate r, for t years is ...

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For the 18.5% loan, the monthly payment is ...

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For the 5% loan, the monthly payment is ...

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The mortgage at 5% would be $1516.69 less per month.

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4 years ago

What is the value of x and y

swat32

Step-by-step explanation:

(25x+8)°+(9x+2)°=180--->(1)(sum of angles on a straight line

(7y+5)°=(9x+2)°------------->(2)(vertical angles)

25x°+8°+9x°+2°=180°

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from equation (2) substitute for x=5°

7y°+5°=9x°+2°

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3 years ago

From the sum of a2−2ab+b2 and 2a2+2ab+b2 subtract the sum of a2−b2 and a2+ab+3b2

Sedaia [141]

Answer:

$a^2-ab$

Step-by-step explanation:

We need to find the sum of $a^2-2ab+b^2$ and $2a^2+2ab+b^2$ first.

Adding $a^2-2ab+b^2$ + $2a^2+2ab+b^2$

Combining like terms, we get

$a^2+2a^2=3a^2$

-2ab+2ab = 0

$b^2+b^2=2b^2$

Therefore,

$a^2-2ab+b^2 +2a^2+2ab+b^2=3a^2+2b^2$ .

Now, we need to find the sum of $a^2-b^2 \ \ and \ \ a^2+ab+3b^2.$ .

Adding $a^2−b^2+a^2+ab+3b^2$ .

Combining like terms, we get

$a^2+a^2=2a^2$

$-b^2+3b^2=2b^2$ .

Therefore,

$a^2−b^2+a^2+ab+3b^2=2a^2+ab+2b^2.$

Now, subtracting

$3a^2+2b^2 -(2a^2+ab+2b^2)$ .

Distributing minus sign over second parenthesis, we get

$3a^2+2b^2-2a^2-ab-2b^2$ .

Combining like terms,

$3a^2-2a^2=a^2$

$2b^2-2b^2=0$

Therefore,

$3a^2+2b^2-2a^2-ab-2b^2=a^2-ab$ .

Therefore, the difference of the sum of $a^2-2ab+b^2$ + $2a^2+2ab+b^2$ and $a^2-b^2+a^2+ab+3b^2.$ is $a^2-ab.$

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3 years ago

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Answer:

C

Step-by-step explanation:

I think this could be it since u have to multiple

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3 years ago

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Well, if you have difficulty with this, just think of it this way:

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Hope this helps, dear <em>high school</em><em> </em>student.

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4 years ago

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