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2 years ago

The oil company removed 5,421 liters of gas from a tank that contained 5,855 liters.

2 answers:

7 0

Liters of gas before they removed some gas = 5,855
Liters of gas AFTER they removed some gas = 5,421
To find how much liters of gas are left,
5,855 - 5,421 = the amount of liters left in the tank
The number of liters left in the tank is 434 Liters.
Oh oh! WAIT! Not done yet! The question asked for MELLILETERS, But we only have liters. <em>Let's convert it!

</em>1 Liter = 1000 ml
434 liters = 1000 × 434
= 434000 ml.

So, the answer to your question is <u>434000 ml</u>.
I hope this helps! ☺

dsp732 years ago

7 0

Answer:

434,000 mL. hope this helped!!

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Multiply (3c+2p)(3c-2p) what is the answer?

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Answer:

9c² -4p²

Step-by-step explanation:

The product of a sum and difference of the same two terms is the difference of their squares:

(3c +2p)(3c -2p) = 3c(3c -2p) +2p(3c -2p)

= (3c)² -6cp +6cp -(2p)²

= (3c)² -(2p)² = 9c² -4p²

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2 years ago

What is the value of the expression StartAbsoluteValue negative 7 EndAbsoluteValue + StartAbsoluteValue negative 4 EndAbsoluteVa

dolphi86 [110]

Answer:

Step-by-step explanation: Because the absoulute value of 8 is 8 then the absoultue value of 7 is 7. Then add them together it equals 15 :)

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2 years ago

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lana [24]

Answer:

i dont know the other questions but i do know the last one and the answer is rhombus.

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2 years ago

Reduce these fractions to the simplest form: 21/42= *

timurjin [86]

Answer:

1/2

Step-by-step explanation:

21 divided by 42 is 1/2

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2 years ago

Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Check al

Alla [95]

Let's rewrite each equation in the Slope-Intercept Form of the Equation of a Line. First, let's start with the main equation:

$\bullet \ 5x-2y=-6 \therefore y=\frac{5}{2}x+3$

Then, our options are the following:

$A) \ y = -\frac{2}{5}x-2 \\ \\ B) \ 2x+5y=-10 \therefore y=-\frac{2}{5}x-2 \\ \\ C) \ 2x-5y=-10 \therefore y=\frac{2}{5}x+2 \\ \\ D) \ y+4=-\frac{2}{5}(x-5) \therefore y=-\frac{2}{5}x-2 \\ \\ E) \ y-4=\frac{5}{2}(x + 5) \therefore y=\frac{5}{2}x+\frac{33}{2}$

For two perpendicular lines it is true that the product of its slopes is:

$m_{1}m_{2}=-1$

$m_{1}m_{2}=-1 \\ \\ m_{1} \ is \ the \ slope \ of \ y=\frac{5}{2}x+3, \ that \ is, \ m_{1}=\frac{5}{2} \\ \\ Then, \ the \ slope \ of \ a \ perpendicular \ line \ is: \\ \\ m_{2}=-\frac{2}{5}$

According to this, only A) B) and D) might be the perpendicular lines we are looking for. Notice that these lines are the same. The other condition is that the line must pass through the point (5, -4). By substituting this point in the equation, we have:

$y = -\frac{2}{5}x-2 \\ \\ -4=-\frac{2}{5}(5)-2 \\ \\ -4=-2-2 \\ \\ \boxed{-4=-4} \ True!$

Finally, the right answer are:

$A) \ y = -\frac{2}{5}x-2 \\ \\ B) \ 2x+5y=-10 \\ \\ D) \ y+4=-\frac{2}{5}(x-5)$

8 0

2 years ago

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