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dexar [7]
3 years ago
7

A. 4/11 B. 7/11 C. 11/7 D. 11/4 help plsss

Mathematics
1 answer:
Vikentia [17]3 years ago
6 0

Answer:

Option B. 7/11

Step-by-step explanation:

The following data were obtained from the question:

Sin x = 7/11

Cos(90 – x) =..?

The value of Cos(90 – x) can simply be obtained as follow:

Recall:

Sin x = Cos(90 – x)

Sin x = 7/11

7/11 = Cos(90 – x)

Therefore, the value of Cos(90 – x) is simply 7/11.

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Answer:

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Step-by-step explanation:

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3 years ago
Please help me I dnt get it
yuradex [85]
The answer would be A and E because the distance (d) is more than 125 miles

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3 years ago
A rose garden Is formed by jolning a rectangle and a semicircle, as shown below. The rectangle Is 23 ft long and 14 ft wide.Find
Ratling [72]

Answer:

Area of the garden:

\begin{equation*} 398.93\text{ ft}^2 \end{equation*}

Explanation:

Given the below parameters;

Length of the rectangle(l) = 23 ft

Width of the rectangle(w) = 14 ft

Value of pi = 3.14

Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.

The radius(r) of the semicircle will now be;

r=\frac{d}{2}=\frac{14}{2}=7\text{ ft}

Let's now go ahead and determine the area of the semicircle using the below formula;

A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2

Let's also determine the area of the rectangle;

A_r=l*w=23*14=322\text{ ft}^2

We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}

Therefore, the area of the garden is 398.93 ft^2

8 0
1 year ago
A number k is less than 3 units from 10. <br> What's the absolute value inequality???
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Step-by-step explanation:

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