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scoray [572]
3 years ago
13

Smh, what is this. If you answer this, please add a prove it statement. Thank you.​

Mathematics
1 answer:
OlgaM077 [116]3 years ago
6 0
28 slices
10 1/2 divided by 3/8 is 28
28 times 3/8 equals 10 1/2
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dianna made several cakes yesterday. each cake required 2 2/3 cups of flour. all together, she used 13 1/3 cups of flours. how m
Kay [80]

13 1/3 divided by 2 2/3

= 40/3 /8/3= 5

Hope that helps!


3 0
3 years ago
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What are the real zeroes of x3 + 6 x2 – 9x - 54?
o-na [289]

Answer:

Option B 3,-3,-6 is correct.

Step-by-step explanation:

We need to find real zeroes of x^3+6x^2-9x-54

Solving

x^3+6x^2-9x-54\\=(x^3+6x^2)+(-9x-54)

Taking x^2 common from first 2 terms and -9 from last two terms we get

=(x^3+6x^2)+(-9x-54)\\=x^2(x+6)-9(x+6)\\

Taking (x+6) common

(x+6)(x^2-9)\\

x^2-9 can be solved using formula a^2-b^2 = (a+b)(a-b)

=(x+6)((x)^2-(3)^2)\\=(x+6)(x+3)(x-3)

Putting it equal to zero,

(x+6)(x+3)(x-3) =0\\x+6 =0, x+3=0\,\, and\,\, x-3=0\\x=-6, x=-3\,\, and\,\,  x=3

So, Option B 3,-3,-6 is correct.

7 0
3 years ago
Find the exact values of the six trigonometric functions of θ if θ is in standard position and the terminal side of θ is in the
mixer [17]
5y - 2x + 1 = 0.
5y = 2x-1.

y = 2/5 x - 2/5

this tells us that tan(theta) = 2/5
sin(theta)/sqrt(1-sin^2(theta)) = 2/5
x/sqrt(1-x^2)=2/5
x^2/(1-x^2)=4/25
25x^2=4-4x^2
29x^2=4
x^2=4/29
x = -2/sqrt(29) because quadrant III
cos(x) = sqrt(1-4/29) = -5/sqrt(29)


tan(theta)=2/5
cos(theta)=-5/sqrt(29)
sin(theta)=-2/sqrt(29)
cot(theta)=5/2
sec(theta)=-sqrt(29)/5
csc(theta)=-sqrt(29)/2
7 0
3 years ago
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How to put 18:3 in simplest form??
Pie
Divide 18 by 3 and you get 3 as an answer
3 0
3 years ago
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Which inequality has a solution set of {x|r> 3 orr<-3)?
s344n2d4d5 [400]
I think it’s B hope so
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