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ycow [4]
3 years ago
8

What value added to x2 − 8x would complete the square?

Mathematics
2 answers:
Mazyrski [523]3 years ago
7 0
X^2 - 8x  = (x - 4)^2 - 16

we add 16 to  give   x^2 - 8x + 16  which is a perfect square 

x^2 - 8x + 16  = (x - 4)^2

answer is 16
andrey2020 [161]3 years ago
5 0

Answer:

16 is added to complete the square

Step-by-step explanation:

x^2-8x

We use completing the square method to complete the square.

In completing the square method, we take coefficient of x and then divide by 2 and square it

\frac{-8}{2} =-4

(-4)^2=16

We add 16 to complete the square

x^2-8x+16

(x-4)(x-4)

(x-4)^2

So, 16 is added to complete the square

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