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marysya [2.9K]
3 years ago
5

One brand of cookies is sold in three different box sizes small medium and large the small box has half the volume of the Box th

e volume of the medium box the volume of the medium boxes X if someone buys one of each size which expression shows the combined volume of the three boxes
Mathematics
1 answer:
lana [24]3 years ago
4 0

this big as dende mf -piccolo

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Mr.Gadgets car broke down on the turnpike.Acme towing charged $30 plus $3 per mile to tow the car.If Mr.Gadget paid $174, how fa
aalyn [17]

The car was towed for 48 miles.

Step-by-step explanation:

Given,

Amount charges by Acme towing = $30

Per mile charges = $3

Total charged = $174

Let, x be the number of miles.

Towing charges + Per mile charges*number of miles = Total charged

30+3x=174

Subtracting 30 from both sides

30-30+3x=174-30\\3x=144

Dividing both sides by 3

\frac{3x}{3}=\frac{144}{3}\\x=48

The car was towed for 48 miles.

Keywords: linear equation, subtraction

Learn more about linear equations at:

  • brainly.com/question/8301701
  • brainly.com/question/8358304

#LearnwithBrainly

8 0
3 years ago
Find the solution of this system of equations shown on the graph.
elena-s [515]
Answer is (0,3)

hope it helps
3 0
3 years ago
Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based
Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for \mathrm{sinc}\,x about x=0:

\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}

Then the Taylor series for

f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt

is obtained by integrating the series above:

f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}

We have f(0)=0, so C=0 and so

f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}

which converges by the ratio test if the following limit is less than 1:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}

Like in the linked problem, the limit is 0 so the series for f(x) converges everywhere.

7 0
3 years ago
Alejandra made the number pattern shown below.
kenny6666 [7]
Jnjjtyyyuuuuuuuuuuuuuuuuu
4 0
3 years ago
Two distinct solid fuel propellants, type A and type B, are being considered for a space program activity. Burning rates of the
Finger [1]

Answer:

C.I. =  (2.297, 11.703)

Step-by-step explanation:

The t-statistic for difference of mean is given by,

t=\frac{\bar{x_{1}}-\bar{x_{2}}}{\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}}

Here, \bar{x_{1}} = 84

\bar{x_{2}} = 7

s₁ = 4

n₁ = 12

s₂ = 6

n₂ = 18

Substituting all value in formula,

We get, t = -3.541 at 28 degree of freedom.

Using this formula, we get, t = 1.5342

Therefore, based on the data provided, the 99% confidence interval for the difference between the population means \bar{x_{1}}-\bar{x_{2}} is: 2.297 < \bar{x_{1}}-\bar{x_{2}} < 11.703

which indicates that we are 99% confident that the true difference between population means is contained by the interval (2.297, 11.703)

6 0
3 years ago
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