Answer:
We conclude that 49x² - 28x + 4 = 0 has only one real root.
Thus, option B i.e. one real root is the correct option.
Step-by-step explanation:
Given the equation
49x² - 28x + 4 = 0
comparing with the quadratic equation ax² + bx + c = 0 for x, where a ≠ 0,
here
a = 49, b = -28, c = 4
Determining the discriminant b²-4ac
b²-4ac = (-28)² - 4(49)(4)
= 784 - 784
= 0
It is clear that the discriminant b²-4ac is equal to zero.
i.e.
b²-4ac = 0
We know that if the discriminant b²-4ac = 0, then the quadratic equation has one real root.
Therefore, we conclude that 49x² - 28x + 4 = 0 has only one real root.
Thus, option B i.e. one real root is the correct option.
