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ipn [44]
3 years ago
11

I need help with this please

Mathematics
1 answer:
djyliett [7]3 years ago
3 0

Answer:

Step-by-step explanation:

The last three are irrational but I'm not sure about the first four.

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If -3(x + 6) = x - 2, then x = -4.
Anon25 [30]

3(x + 6) = x - 2

3(-4+6)= -4-2

mutiply the bracket by 3

(3)(-4)= -12

(3)(6)= 18

-12+18= -4-2

6= -4-2

6= -6

Answer:

No solution

4 0
3 years ago
he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s
sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

P(X

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) =[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

NORMSDIST(6.366)-NORMSDIST(-1.47)

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0
3 years ago
Help me with this please​
BabaBlast [244]
It’s d, d is the right answer
7 0
3 years ago
Read 2 more answers
The area of the shaded region to the nearest tenth is __________.
goldfiish [28.3K]

Answer: 380 ft^2

Step-by-step explanation:

Length of sides of square=25

Diameter of semicircle=25

Radius=r=25/2=12.5

π=3.14

Area of square=length x length

Area of square=25 x 25=625

Area of semicircle=0.5 x π x r x r

Area of semicircle=0.5 x 3.14 x 12.5 x 12.5

Area of semicircle=245.3125

Area of shaded portion=area of square - area of semicircle

Area of shaded portion=625-245.3125

Area of shaded portion=379.6875

Area of shaded portion=380ft^2

approximately

4 0
3 years ago
How do I solve these problems I'm trying to find the cheapest deal
atroni [7]
2.79 / 2 = 1.395 rounds to 1.40 per roll
8.99 / 6 = 1.498 rounds to 1.50 per roll

the better deal (cheapest) is the 2 roll package

** if u want price per roll (price / roll) ...u divide the price by the number of rolls
7 0
3 years ago
Read 2 more answers
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