Answer:
y=2x+6
Step-by-step explanation:
y=mx+b
your two point that are [-1, 4] with 1 as x and 4 as y
replace y with 4 then replace m with 2 then put your negative one in () it should look like this
4=2(-1)+b then do what in Parentheses
that will give you -2 then add 2 to 4 and that will give u 6
y=2x+6
The absolute value of a real number is a positive value of the number. Which means that the absolute value is the distance from zero of the number line. However, that of the complex numbers is the distance from the origin to the point in a complex plane.
I think it is -2288 something like that
Answer:
4/3
Step-by-step explanation:
The tangent of any angle (θ) in standard position that has point (x, y) on its terminal ray is ...
tan(θ) = y/x
__
For the given point on the terminal side, the tangent is ...
tan(θ) = (-4)/(-3) = 4/3
_____
<em>Additional comment</em>
There are several ways this can be explained. One of them makes use of the relation between rectangular and polar coordinates:
(x, y) = (r·cos(θ), r·sin(θ))
Then the ratio y/x is ...
y/x = (r·sin(θ))/(r·cos(θ)) = sin(θ)/cos(θ) = tan(θ)
The area of square is
square units
<h3><u>Solution:</u></h3>
Given that square has side length (x+5) units
To find: area of square
<em><u>The area of square is given as:</u></em>
![\text {Area of square }=\mathrm{a}^{2}](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20of%20square%20%7D%3D%5Cmathrm%7Ba%7D%5E%7B2%7D)
Where "a" is the length of side
From question, length of each side "a" = x + 5 units
Substituting the value in above formula,
![\text {Area of square }=(x+5)^{2}](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20of%20square%20%7D%3D%28x%2B5%29%5E%7B2%7D)
![{\text {Expanding }(x+5)^{2} \text { using the algebraic identity: }} \\\\ {(a+b)^{2}=a^{2}+2 a b+b^{2}}\end{array}](https://tex.z-dn.net/?f=%7B%5Ctext%20%7BExpanding%20%7D%28x%2B5%29%5E%7B2%7D%20%5Ctext%20%7B%20using%20the%20algebraic%20identity%3A%20%7D%7D%20%5C%5C%5C%5C%20%7B%28a%2Bb%29%5E%7B2%7D%3Da%5E%7B2%7D%2B2%20a%20b%2Bb%5E%7B2%7D%7D%5Cend%7Barray%7D)
![\begin{array}{l}{\text {Area of square }=x^{2}+2(x)(5)+5^{2}} \\\\ {\text {Area of square }=x^{2}+10 x+25}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Ctext%20%7BArea%20of%20square%20%7D%3Dx%5E%7B2%7D%2B2%28x%29%285%29%2B5%5E%7B2%7D%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7BArea%20of%20square%20%7D%3Dx%5E%7B2%7D%2B10%20x%2B25%7D%5Cend%7Barray%7D)
Thus the area of square is
square units