The area of the banner is 144 square feet. The width of the banner is 1/4 the length of the banner. What are the dimensions of
the banner?
2 answers:
Answer:
The width is 6 and the length is 24.
Step-by-step explanation:
You need to create an equation using the area, because we know that the width is 1/4 of the length we can use x for both values:




Then you can use this to find the width and the length.
The width is 6 ft. The length is 24 ft!
You might be interested in
Answer:
5 times larger
Step-by-step explanation:
5*10^5 = 500,000
1*10^5 = 100,000
500,000/100,000 = 5
40 x 5280 = 211200 feet per hour
211200 / 3600 = 58.666 = 59 feet per second
Answer:
EA
Step-by-step explanation:
Check the picture below.
![\bf \stackrel{\textit{area of triangles on the left}}{2\left[\cfrac{1}{2}(2)(3) \right]}+\stackrel{\textit{area of triangles on the right}}{2\left[\cfrac{1}{2}(4)(3) \right]}\implies 6+12\implies 18](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20triangles%20on%20the%20left%7D%7D%7B2%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%282%29%283%29%20%5Cright%5D%7D%2B%5Cstackrel%7B%5Ctextit%7Barea%20of%20triangles%20on%20the%20right%7D%7D%7B2%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%284%29%283%29%20%5Cright%5D%7D%5Cimplies%206%2B12%5Cimplies%2018)
Hopes this helps below if it did please say thanks on the button or make me the brainiest:)