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2 years ago

Use SOHCAHTOA for this. Work out 'm' in 3sf, I need the working out.

Mathematics

1 answer:

Lady bird [3.3K]2 years ago

7 0

Anwer:3.537m

STEP BY STEP EXPLANATIOND:using SOH CAH TOA

First find the opposite

Represent the opposite with x

Tan 33° =x\10

x=10Tan 33°

x=6.494

To find m

Sin 33°=m\6.494 Sin 33°

m=3.5368

m=3.537meteres

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If EF bisects CD, CG =5x-1, GD = 7x-13, EF = 6x-4, and GF =13, find EG

VARVARA [1.3K]

Greetings from Brasil....

As stated in the statement of the question, EF is a bisector of CD, so point G is the median point of CD, so CG = GD

5X - 1 = 7X - 13

X = 6

EF = EG + GF

6X - 4 = EG + 13 x = 6, so

6·6 - 4 = EG + 13

(see attachment)

6 0

2 years ago

You are given g(x)=4x^2 + 2x and

Strike441 [17]

Answer:

324

Step-by-step explanation:

Given:

$g(x)=4x^2+2x\\ \\f(x)=\int\limits^x_0 {g(t)} \, dt$

Find:

$f(6)$

First, find f(x):

$f(x)\\ \\=\int\limits^x_0 {g(t)} \, dt\\ \\=\int\limits^x_0 {(4t^2+2t)} \, dt\\ \\=\left(4\cdot \dfrac{t^3}{3}+2\cdot \dfrac{t^2}{2}\right)\big|\limits^x_0\\ \\=\left(\dfrac{4t^3}{3}+t^2\right)\big|\limits^x_0\\ \\= \left(\dfrac{4x^3}{3}+x^2\right)-\left(\dfrac{4\cdot 0^3}{3}+0^2\right)\\ \\=\dfrac{4x^3}{3}+x^2$

Now,

$f(6)\\ \\=\dfrac{4\cdot 6^3}{3}+6^2\\ \\=288+36\\ \\=324$

4 0

2 years ago

Folding a rectangle along one diagonal results in a shape whose area is 2/3 that of the original

Charra [1.4K]

Answer:

60°

Step-by-step explanation:

Refer to attached picture

Given rectangle ABCD. Its folded shape is given as well.

It has sides a and b and diagonal d, with the angle BCD marked as α.

We need to find the value of angle AOC or BOD.

This is going to be 2α, which is easy to find out. BOD is cut by the angle bisector, each of the angles is α.

Let the area of the rectangle is A, then the folded shape has area 2/3A.

The area of rectangle ABCD:

A = ab

From the triangle CBD we get:

a/d = sin α ⇒ a = d sin α
b/d = cos α ⇒ b = d cos α

Then

A = d sin α * d cos α = d²sin α cos α

Now, lets find the area of the folded shape.

It is the area of the rectangle minus the area of the triangle CMB as this part is lost as part of overlap.

Area of the triangle:

A = 1/2dh

Since h/(d/2) = tan α ⇒ h = 1/2d tan α, the area is:

A = 1/2d*1/2d tan α = 1/4d² tan α

We have the difference of the areas which is 1/3 of the area of the rectangle:

1/3(d²sin α cos α) = 1/4d² tan α
sin α cos α = 3/4 tan α
sin α cos α = 3/4 sin α / cos α
cos² α = 3/4
cos α = √(3/4)
cos α = √3/2
α = arccos (√3/2)
α = 30°

The acute angle formed by the two diagonals of the rectangle is:

2α = 2*30° = 60°

3 0

2 years ago

What is the next term in the following sequence?

enot [183]

-2
Explanation:
You divide by -3each time
54/-3 = -18
-18/-3 = 6
6/-3 = -2

7 0

2 years ago

Simplify 6(-5). -30 -11 1 30

Pavel [41]

If you would like to simplify 6 * (-5), you can do this using the following steps:

6 * (-5) = - (6 * 5) = - 30

The correct result would be - 30.

8 0

3 years ago

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