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Liono4ka [1.6K]
3 years ago
12

What is the value of x... 5(x-5)=3(x-7)

Mathematics
1 answer:
timurjin [86]3 years ago
8 0

Answer:

x=2

Step-by-step explanation:

5(x-5)=3(x-7)

Distribute

5x-25 = 3x-21

subtract 3x from each side

5x-25-3x = 3x-21-3x

2x-25 = -21

Add 25 to each side

2x-25+25 = -21 +25

2x=4

Divide by 2

2x/2 =4/2

x=2

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1.
adoni [48]

Answer:

y = |x| - 1

Step-by-step explanation:

The difference between the parent function (y=|x|) and the graph, is that the graph is 1 unit down. y = |x| -1 has the parent function 1 unit down

3 0
2 years ago
Read 2 more answers
A cube has a side length of 5xcm. What is the volume of the cube?<br>no links please.​
finlep [7]

Answer:

125 cm

Step-by-step explanation:

V=lwh

all cube has the same length, width, height

5 * 5 * 5 = 125

Hope this helps

7 0
3 years ago
Round 6.7086 to the nearest thousandth
Bingel [31]

\text {Hello! Let's solve this Problem!}

\text {To round to the nearest thousandth you must underline the thousandth place}\text {(which is 8), point an arrow to 6 (in the ten-thousandth place)}

\text {If the number is 5 or more you raise the score. Meaning you add 1 to the}\text {thousandth place. If the number is 4 or lower you keep the number the same.}

\text {6 is greater than 5. So this means you add 1 to 8 and it becomes 9. Every}\text {number behind it becomes 0.}

\text {Your Answer Would Be:}

\huge\boxed {\text {6.7090 or 6.709}}

\text {Best of Luck!}

7 0
3 years ago
Need answers ASAP I got less than 20 mins thx
kotegsom [21]

Answer: PQ = 18

Step-by-step explanation:

You would divide 21/14 to see what the size difference in the triangles is to get 1.5. 1.5x12=18

7 0
3 years ago
Read 2 more answers
A factory worker productivity is normally distributed. one worker produces an average of 75 units per day with a standard deviat
Angelina_Jolie [31]
Let Xi be the random variable representing the number of units the first worker produces in day i.
Define X = X1 + X2 + X3 + X4 + X5 as the random variable representing the number of units the
first worker produces during the entire week. It is easy to prove that X is normally distributed with mean µx = 5·75 = 375 and standard deviation σx = 20√5.
Similarly, define random variables Y1, Y2,...,Y5 representing the number of units produces by
the second worker during each of the five days and define Y = Y1 + Y2 + Y3 + Y4 + Y5. Again, Y is normally distributed with mean µy = 5·65 = 325 and standard deviation σy = 25√5. Of course, we assume that X and Y are independent. The problem asks for P(X > Y ) or in other words for P(X −Y > 0). It is a quite surprising fact that the random variable U = X−Y , the difference between X and Y , is also normally distributed with mean µU = µx−µy = 375−325 = 50 and standard deviation σU, where σ2 U = σ2 x+σ2 y = 400·5+625·5 = 1025·5 = 5125. It follows that σU = √5125. A reference to the above fact can be found online at http://mathworld.wolfram.com/NormalDifferenceDistribution.html.
Now everything reduces to finding P(U > 0) P(U > 0) = P(U −50 √5125 > − 50 √5125)≈ P(Z > −0.69843) ≈ 0.757546   .
5 0
3 years ago
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