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Vladimir79 [104]

3 years ago

10

I have a 84% in class, there is a 25 point quiz worth 100 points, how what grade do I need to get to at least have an average gr

ade of an A

2 answers:

Delicious77 [7]3 years ago

8 0

A 93%-96%

A- 90%-92%

B+ 87%-89%

B 83%-86%

Thepotemich [5.8K]3 years ago

4 0

At least about 20 points it can depend on the class but not really.

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Researchers for the University of Maryland Department of Civil and Environmental Engineering used stochastic dynamic programming

aalyn [17]

Answer:

Check the explanation

Step-by-step explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

6 0

3 years ago

Find x. <br> Side splitter theorem

professor190 [17]

Answer:

x = 9

Step-by-step explanation:

The outer and inner triangles are similar, thus the ratios of corresponding sides are equal, that is

$\frac{8}{8+4}$ = $\frac{x-3}{x}$ , that is

$\frac{8}{12}$ = $\frac{x-3}{x}$ ( cross- multiply )

12(x - 3) = 8x

12x - 36 = 8x ( subtract 8x from both sides )

4x - 36 = 0 ( add 36 to both sides )

4x = 36 ( divide both sides by 4 )

x = 9

3 0

3 years ago

The graph of a function f(x) is shown below:<br><br><br><br> What is the domain of f(x)?

Pie

The domain is the scope of the x values. In this case (-2,-1) is a hole, so x>-2 is one end of the domain, while (3,3) is defined. So the domain using interval notation is (-2,3] which can also be expressed -2 < x ≤ 3, answer option 1

8 0

3 years ago

Consider the following division of polynomials.

Bond [772]

$x^4=x^2\cdot x^2$ . Multiplying the denominator by $x^2$ gives

$x^2(x^2+2x+8)=x^4+2x^3+8x^2$

Subtracting this from the numerator gives a remainder of

$(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8$

$-x^3=-x\cdot x^2$ . Multiplying the denominator by $-x$ gives

$-x(x^2+2x+8)=-x^3-2x^2-8x$

and subtracting this from the previous remainder gives a new remainder of

$(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8$

This last remainder is exactly the same as the denominator, so $x^2+2x+8$ divides through it exactly and leaves us with 1.

What we showed here is that

$\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}$

$=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}$

$=x^2-x+1$

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

$(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)$

$=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)$

$=x^4+x^3+7x^2-6x+8$

which matches the original numerator.

3 0

3 years ago

Read 2 more answers

What does this equal y >4x - 5

Tresset [83]

Answer:

This represents the graph area above the line y = 4x - 5 shaded.

Step-by-step explanation:

y > 4x - 5 is an inequality. First we graph y = 4x - 5, which has y-intercept (0, -5) and slope 4. Next, we shade all of the area above this line (because the inequality y > 4x - 5 says that all y values are above 4x - 5).

3 0

3 years ago