Question

Can you prove triangle BAC is similar to triangle DFE ? Justify your answer.

Answer 1

You can use side-angle-side postulate 

Answer 2

Answer:

By AA property of similarity, triangles BAC and DFE are similar.

Step-by-step explanation:

Given information: AC║FE and AB║FD.

If a transversal line intersect two parallel lines, then the corresponding angles are equal.

In triangle BAC and triangle DFE

$\angle ABC=\angle FDE$                  (corresponding angles)

$\angle ACB=\angle FED$                  (corresponding angles)

Two corresponding angles of triangles are equal. So, by AA property of similarity both triangles BAC and  DFE are similar.

$\triangle BAC\sim \triangle DFE$

Hence proved.