We are given with the variable cost which is:
q = -20s + 400
The selling price is 's'. So, the profit can be represented by:
P = qs - q(12)
Subsituting:
P = (-20s + 400)s - 12 (-20s + 400)
P = -20s^2 + 640s - 4800
To optimize this, we must differentiate the equation and equate it to zero, so:\
dP/ds = -40s + 640 = 0
Solving for s,
s = 16
So, the selling price should be $16 to optimize the yearly profit.
Answer:
use pythagoras theorem to solve ur problem.
Answer:
BC= 23.0km (nearest tenth)
Step-by-step explanation:
Please see the attached picture for full solution.
Answer:
<h3>
x = 2</h3><h3 />
Step-by-step explanation:
use Pythagorean theorem:
a² + b² = c²
where a = x
b = 8/2 = 4
c = √20
plugin values into the formula:
x² + 4² = (√20)²
x² + 16 = 20
x² = 20 - 16
x = √4
x = 2
Answer:
-6
Step-by-step explanation:
the x value is just plugging that number in for x so
-3x-8=10 (add 8 to both sides) so
-3x=18 (divide by -3 on both sides) so
x=-6
