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n200080 [17]
3 years ago
12

What UDP port is used by a default WDS server setup when it is listening for PXE boot requests​

Computers and Technology
1 answer:
Vera_Pavlovna [14]3 years ago
8 0
WDS uses Port 4011 to listen to PXE boot requests
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inna [77]
I have never seen this in my life sorry
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I need help, who is a great phone pin lock screen cracker?
svlad2 [7]

Answer:

738159

now it's depend on you.

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Consider a single CPU system with an active process A. Explain what happens in the following circumstances including any interru
Anika [276]

Answer:

The answer to this question as follows:

Explanation:

In option a, When we use fork, a new mechanism, that uses fork() method, which is in the parental process, to replicate all sites. It has been installed in a space-differentiating operating system.

In option b, It is the present system cycle that scan and wait for any of the system processor to be installed.

In option c,  The time delay happens when A operates. It is a global that make issues, which are cleared and slowed down when an interrupt happens. In this process, there are not any distractions. It splits into slowly as it heads into the ISR. It helps to understand the code easily.

5 0
3 years ago
Given public class Fishing { byte b1 = 4; int i1 = 123456; long L1 = (long) i1; //Line A short s2 = (short) i1; //Line B byte b2
Aleksandr [31]

Answer:

Line E.

Explanation:

The  given program is as follows:

public class Fishing {

   byte b1 = 4; int i1 = 123456; long L1 = (long) i1;   //Line A

   short s2 = (short) i1;     //Line B

   byte b2 = (byte) i1;     //Line C

   int i2 = (int)123.456;    //Line D

   byte b3 = b1 + 7;     //Line E

   }

In the above code Line E will not compile and give following compilation error:

error: incompatible types: possible lossy conversion from int to byte

This error is coming because in Java b1 + 7 will be interpreted as int variable expression. Therefore in order to make code of Line E work the expression should be type casted as byte.  

The correct code will be as follows:

public class Fishing {

   byte b1 = 4; int i1 = 123456; long L1 = (long) i1;   //Line A

   short s2 = (short) i1;     //Line B

   byte b2 = (byte) i1;     //Line C

   int i2 = (int)123.456;    //Line D

   byte b3 = (byte)(b1 + 7);     //Line E

   }

5 0
3 years ago
Nonprocedural access to a database
777dan777 [17]

Answer:

Option D: All of above.

is the correct answer.

Explanation:

  • Non-procedural access is the feature of the database.
  • This means that when a database is created in a database management system (DBMS) using data definition language (DDL), it will be accessed every time using a data manipulation language (DML). The standard DML is SQL. SQL stands for Sequential Query Language.
  • This feature of database ultimately improves the software productivity.
  • Most of the tools of Database Management systems (DBMSs) support the non-procedural access.
  • This feature permits a user to submit queries to a database without knowing how to retrieve data.

i hope it will help you!

4 0
3 years ago
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