It should be noted that the process of redefining the functionality of a built-in operator to operate is known as <u>operator overloading</u>.
Operator overloading simply means polymorphism. It's a manner in which the operating system allows the same operator name to be used for different operations.
Operator overloading allows the operator symbols to be bound to more than one implementation. It's vital in redefining the functionality of a built-in operator to operate on programmer-defined objects.
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Answer:
The answer to this question is given below in the explanation section
Explanation:
The correct answer is RAM.
RAM is used for storing programs and data currently being processed by the CPU. So, the data in the RAM, can be easily accessible and processed by the CPU more fastly.
While Mass memory and neo volatile memory is not correct options. because these types of memory can stores a large amount of data but CPU fetch data from these memories into RAM. and, RAM can only be used by the CPU when performing operations.
Answer:
- def ending_time(hour, minutes, seconds, work_time):
- if((seconds + work_time) // 60 > 0):
- minutes = minutes + (seconds + work_time) // 60
- seconds = (seconds + work_time) % 60
-
- if(minutes // 60 > 0):
- hour = hour + (minutes // 60)
- minutes = minutes % 60
- else:
- seconds = seconds + work_time
-
- return str(hour) + ":" + str(minutes) + ":" + str(seconds)
-
- print(ending_time(2,30,59, 12000))
Explanation:
The solution code is written in Python 3.
Firstly create a function ending_time that takes the four required input parameters.
Next, create an if statement to check if the numerator of (seconds + work_times) divided by 60 is over zero. If so, increment the minute and reassign the remainder of the seconds to the variable (Line 2-4).
Next, create another if statement again to check if the numerator of (current minutes) divided by 60 is over zero, if so increment the hour and reassign the remainder of the minutes to the variable (Line 6-8)
Otherwise, just simply add the work_time to the current seconds
At last return the time output string (Line 12).