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2 years ago

. A possible data for source that could be used when completing a mail merge could be a(n)… : *

Computers and Technology

2 answers:

igor_vitrenko [27]2 years ago

8 0

Answer: d) All of the above

Explanation: Mail merge is the technique in which the emails are combined with the predefined labels so that it could be mass mailed. This tool is helpful for sending a mail to several people at one time. Data source that is used in the mass mailing is known as the database that holds a column for variables present in templates.

Therefore, outlook contact list, excel sheet access database table,word table etc can be used as the source of data at the time of mail merge.These tools acts as data source to connect with the templates.Data source is the source that contains the information about the recipient such as address etc.

Thus all the options mention in the question are correct.

Hatshy [7]2 years ago

6 0

A possible data for source that could be used when completing a mail merge could be all the above.

d. all the above

Explanation:

Mail merge allows one to send a particular document to different individuals.

It is generally used in office environment where some information is to be communicated to a number of people. The information is attached by adding the data sources.

The information source is a report, spreadsheet or database that contains customized data, for example, names, locations, and telephone numbers.

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Which is an unbound form with menu options for navigating a database?

melisa1 [442]

The answer B. a switchboard

6 0

3 years ago

Read 2 more answers

Write c++ program to find maximum number for three variables using statement ?

pantera1 [17]

Answer:

#include<iostream>

using namespace std;

int main(){

int n1, n2, n3;

cout<<"Enter any three numbers: ";

cin>>n1>>n2>>n3;

if(n1>=n2 && n1>=n3){

cout<<n1<<" is the maximum";}

else if(n2>=n1 && n2>=n3){

cout<<n2<<" is the maximum";}

else{

cout<<n3<<" is the maximum";}

return 0;

}

Explanation:

The program is written in C++ and to write this program, I assumed the three variables are integers. You can change from integer to double or float, if you wish.

This line declares n1, n2 and n3 as integers

int n1, n2, n3;

This line prompts user for three numbers

cout<<"Enter any three numbers: ";

This line gets user input for the three numbers

cin>>n1>>n2>>n3;

This if condition checks if n1 is the maximum and prints n1 as the maximum, if true

if(n1>=n2 && n1>=n3){

cout<<n1<<" is the maximum";}

This else if condition checks if n2 is the maximum and prints n2 as the maximum, if true

else if(n2>=n1 && n2>=n3){

cout<<n2<<" is the maximum";}

If the above conditions are false, then n3 is the maximum and this condition prints n3 as the maximum

else{

cout<<n3<<" is the maximum";}

return 0;

3 0

3 years ago

Distinguish between formal and Informal Information System Information systems

Harlamova29_29 [7]

Explanation:

Formal; A formal information system is based on

the organization represented by the organization chart.

Informal; The informal information system is

employee based system designed

to meet personal and vocational needs

and to help in solution of work-related problems.

5 0

2 years ago

Place the optical discs in the increasing order of storage capacity. UDO CD DVD

romanna [79]

<h2>Hello!</h2>

The answer is:

Optical disks are circular disks used as storage for binary data usually made of polycarbonate. The data is stored in the disc using a laser machine and accessed using a laser diode illuminating the data path in an optical disc drive.

CD: Compact Discs are the most basic optical disk used today, with only a capacity that goes from 0.7 GB (700 MB) to 0.84 GB (840 MB).

DVD: Digital Versatile Discs increase the storage up to 6 times compared with a CD, the capacity of DVDs optical disks goes from 4.7 GB (4700 MB) to about 17 GB(17000 MB).

UDO: Ultra Density Optical have high capacity storage that goes from 30 GB (30000 MB) to about 60 GB (6000 MB).

Have a nice day!

4 0

3 years ago

5)What are the differences in the function calls between the four member functions of the Shape class below?void Shape::member(S

Stells [14]

Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. const keyword restricts us so we cannot make any change to s1 or s2 object as well as the Shape function itself.

5 0

3 years ago