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4 years ago

What are the zeros of the function f(x) = x +5 – 2x2?

Mathematics

1 answer:

MA_775_DIABLO [31]4 years ago

5 0

Answer:

x = -1

Step-by-step explanation:

First things first, simplify;

x+5 - 2(2)

x+5 - 4

x+1

Now we have;

f(x) = x+1

subtract 1

x = -1

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Is -10.5 a rational number?

sladkih [1.3K]

Yes it is a rational number it can be expressed as a fraction

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3 years ago

Please help me with this question asap!!!

Varvara68 [4.7K]

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5 0

3 years ago

Read 2 more answers

7+ax-5x=3+2x-bx <img src="https://tex.z-dn.net/?f=7%20%20%2B%20ax%20-%205x%20%3D%203%20%2B%202x%20-%20bx" id="TexFormula1" ti

butalik [34]

Answer:

a = −bx+7x−4 over x

Step-by-step explanation:

solve for a:

7+ax−5x=3+2x−bx

add 5x to both sides:

ax−5x+7+5x=−bx+2x+3+5x

ax+7=−bx+7x+3

add -7 to both sides:

ax+7+−7=−bx+7x+3+−7

−bx+7x−4

lastly divide both sides by x.

7 0

3 years ago

Given three different prime numbers <img src="https://tex.z-dn.net/?f=p_1%20%5C%20%5C%20%3B%20%5C%20%5C%20p_2" id="TexFormula1"

Stels [109]

Answer:

19982

Step-by-step explanation:

As we know all primes but 2 are odd numbers.

It means sum of any 3 primes not including 2 is odd.

Since we have sum of 202, one of our primes is 2.

Sum of the other two primes is 200.

In order to have maximum value of p*(200 - p) these two numbers must be closer to each other. So we are looking for two primes around 100.

We can test all primes less than 200:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, and 199

The 3 primes with max product are:

2, 97, 103

The value is:

2*97*103 = 19982

8 0

3 years ago

Find the HCF and LCM of 160 and 252 by prime factorisation method and verify that HCF x LCM = Product of the two given numbers.

MariettaO [177]

Answer:

HCF=4

LCM=10080

HCF x LCM = Product of the two given numbers is verified because 403200=40320

Step-by-step explanation:

HCF of 160 and 252

HCF is the product of common prime factors

Prime Factorisation of 160: 2x2x2x2x2x5

Prime Factorisation of 252: 2x23x3x7

HCF= 2x2

HCF=4

40 and 63 doesn't come in any other table together so,

HCF= 2 x 2 = 4

Now, finding LCM of 160 and 252

LCM is the product of all factors of both numbers, while if any factor is common, it is considered once.

Prime Factorisation of 160: 2x2x2x2x2x5

Prime Factorisation of 252: 2x23x3x7

In the given factors 2x2 is common so, it is considered once.

LCM= 2x2x2x2x2x3x5x7

LCM= 10080

Now, checking:

HCF x LCM = Product of the two given numbers.

4x10080=160x252

403200=40320

So, It is verified that HCF x LCM = Product of the two given numbers.

7 0

3 years ago