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alexandr1967 [171]
3 years ago
15

Which algebraic expression is a difference with two terms?

Mathematics
1 answer:
ipn [44]3 years ago
4 0
Its a because it's a 6)×+5
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Please help with this its my last problem and im lost
Natasha2012 [34]

4\sqrt{10xy^3\\

and then there's a line with 2y right under that expression

8 0
2 years ago
If x = 2 and y = -3, what is the value of 2x^2−3xy−2y^2<br> HELPPP
oksano4ka [1.4K]

Answer:

8

Step-by-step explanation:

2(2)^2‒3(2*‒3)‒2(‒3)^2

2*4‒3(‒6)‒2(9)

8‒(‒18)‒18

8+18‒18

26‒18

8

i think it is easy to understand &i hope it will helps you

8 0
3 years ago
Find cos(B) in the triangle.<br> Choose 1 answer:
Leno4ka [110]
Cosine: adjacent/hypothenuse
Adjacent = 3, hypothenuse = 5

Solution: 3/5
5 0
3 years ago
Solve for X, (with steps please) <br> 0.46=0.527-[0.0562/2 * log(0.1+x/1.5-x)]
Ivanshal [37]
Rearrange the equation: 

\frac{0.0562}{2} * log( \frac{0.1+x}{1.5 - x}) = 0.527 - 0.46 = 0.067

Isolate the log on its own

log (\frac{0.1 + x}{1.5 - x}) = \frac{0.067*2}{0.0562} = 2.42 (2dp)

To get rid of the log you must do 10^2.42 

\frac{0.1 +x}{1.5-x} = 10^{2.42} = 242.29 (2dp)

Then multiply both sides by (1.5 - x)

0.1 +x = 242.29(1.5-x)

0.1 + x = 363.44 - 242.29x

Solve normally

243.29x = 363.34    x = 363.34/243.29    x= 1.49344    x= 1.49 (2dp)

Hope that helps. Please send me a message if there's patchy bits. Also I'm sure you'll figure this out, but just in case, anywhere I've put down a 2dp shows that I've rounded the number to 2 decimal places. It becomes a pain to deal with otherwise. 

3 0
3 years ago
MMMMMMMMMMHHHHHHHHHHHHHHHHHHH
Setler [38]

Answer:

MMMMMMMMMMHHHHHHHHHHHHHHHHHHHMMMMMMMMMMHHHHHHHHHHHHHHHHHHHMMMMMMMMMMHHHHHHHHHHHHHHHHHHHMMMMMMMMMMHHHHHHHHHHHHHHHHHHHMMMMMMMMMMHHHHHHHHHHHHHHHHHHHMMMMMMMMMMHHHHHHHHHHHHHHHHHHHMMMMMMMMMMHHHHHHHHHHHHHHHHHHHMMMMMMMMMMHHHHHHHHHHHHHHHHHHHMMMMMMMMMMHHHHHHHHHHHHHHHHHHHMMMMMMMMMMHHHHHHHHHHHHHHHHHHHMMMMMMMMMMHHHHHHHHHHHHHHHHHHHMMMMMMMMMMHHHHHHHHHHHHHHHHHHH

Step-by-step explanation:

can i have brainliest??

4 0
2 years ago
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