Question

Shawn wants to use an elevator to carry identical packages having the same weight. Each package weighs 5 pounds and Shawn weighs 100 pounds. If the elevator can carry a maximum of 340 pounds at a time, which inequality shows the maximum number of packages, n, that Shawn can carry with himself in the elevator if he is the only passenger

Answer 1

Answer: $n\leq48$

Step-by-step explanation:

Let n be the maximum number of packages, that Shawn can carry with himself in the elevator if he is the only passenger.

Since each package weighs 5 pounds and Shawn weighs 100 pounds.

Total weight = Shawn's weight + (Weight of each package ) x (Number of packages)

= 100+5n

Since , the elevator can carry a maximum of 340 pounds at a time , then

$100+5n\leq340$

Subtract 100 from both sides , we get

$5n\leq240$

Divide both sides by 5 , we get

$n\leq48$

So , the inequality shows the maximum number of packages, n, that Shawn can carry with himself in the elevator if he is the only passenger is $n\leq48$.

Answer 2

Answer:

n is less than or equal to 48.

Step-by-step explanation:

He weighs 100 lbs.

So: 340 - 100 = 240 - remaining weight for packages.

240/5 = 48.

He can carry 48 packages at most with him.