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LenaWriter [7]
4 years ago
15

I need help, I don’t understand how to do this

Mathematics
2 answers:
Leni [432]4 years ago
3 0

Answer:

8 and -8

Step-by-step explanation:

an absolute value will always be positive. So if you see a number like this l-8l, it will be positive

den301095 [7]4 years ago
3 0
Another way to say absolute value is like saying distance from 0. So if you want numbers with an absolute value of 8. The answer would be 8 and -8.
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A cone has a diameter of 10 inches. If its height is twice its radius, about what is the volume of the cone in cubic inches? Use
GuDViN [60]

Answer:

C) 261.67 inch³

Step-by-step explanation:

radius = 10/2 = 5

height = 10

Volume = ⅓×pi×r²×h

= ⅓×3.14×5²×10

= 261.6666666667

6 0
3 years ago
How do i solve for x? *you have to show work*
eduard
1) Factor the equation first:

2e^{2x} + 4xe^{2x} = 0
e^{2x}(2 + 4x) = 0

So either e^{2x} = 0 or 2 + 4x = 0. But e^{2x} = 0 can never equal 0! So, we only need to solve for the second equation:

2 + 4x = 0
\bf x = {-\frac{1}{2}}

2) First, single out the term with the exponent:

2 + 3(4^{2x - 1}) = 43
3(4^{2x - 1}) = 41
4^{2x - 1} = \frac{41}{3}

Now, taking the log base 4 of each side gives us

2x - 1 = \log_4 \frac{41}{3}

and we can now solve for x:

2x - 1 = \log_4 \frac{41}{3}
2x = 1 + \log_4 \frac{41}{3}
2x = \log_4 4 + \log_4 \frac{41}{3}
2x = \log_4 \frac{164}{3}
x = \frac{1}{2} \log_4 \frac{164}{3}
x = \log_4 \sqrt \frac{164}{3}
\bf x = \log_4 2 \sqrt \frac{41}{3}
8 0
3 years ago
7)
saul85 [17]

Answer:

B

Step-by-step explanation:

7 0
4 years ago
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3 years ago
What is the answer to the area question
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