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1 year ago

Mat played tennis 35 times in 7 weeks. sue played tennis 15 times in 21 days. are their rates equivalent?

1 answer:

5 0

Yes they are because you convert 7 weeks to days. Then you divide 49 by 21 because you have to see if they go in with each other and do the same thing with 35 and 15.

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Suppose that many large samples are taken from a population and that the

rewona [7]

Answer:

$0.22 -1 *0.029 =0.191$

$0.22 +1 *0.029 =0.249$

And the best option would be:

D. (0.191 to 0.249)

Step-by-step explanation:

For this case we know that the mean is:

$\bar X = 0.22$

And the standard error is given by:

$SE = 0.029$

We want to construct a 68% confidence interval so then the significance level would be :

$\alpha=1-0.68 = 0.32$ and $\alpha/2 =0.16$ . The confidence interval is given by:

$\bar X \pm z_{\alpha/2} SE$

Now we can find the critical value using the normal standard distribution and we got looking for a quantile who accumulate 0.16 of the area on each tail and we got:

$z_{\alpha/2}= 1$

And replacing we got:

$0.22 -1 *0.029 =0.191$

$0.22 +1 *0.029 =0.249$

And the best option would be:

D. (0.191 to 0.249)

5 0

3 years ago

Write each number as a product of the GCF and another sum. Then use the Distributive Property to rewrite the sum. 45 + 30 = (15

Lorico [155]

Answer:

x=5/2

Step-by-step explanation:

Calculate, rewrite, remove the paretheses

Collect the like terms

Swap sides 75=30x swap to 30x=75

Then divide both sides

3 0

3 years ago

Help me find the graph plz

olga2289 [7]

The first one is (1,10)
The second one is (1,5)
The third one is (0.5,10)
I hope this helps

8 0

3 years ago

Read 2 more answers

Noah made 12 kg of trail mix for his family's hiking trip. His family ate 8,600 g of the trail mix on the hiking trip.

Alborosie

Noah had 3,400 grams left

5 0

3 years ago

If sin theta = -5/7 , which of the following are possible?

Sav [38]

Solution:

we are given that

$sin \theta=-5/7$

As we know that

$cos \theta =\sqrt{1-sin^2 \theta} \\$

Substitute the value we get

$cos \theta=\sqrt{1-(\frac{-5}{7})^2} \\
\\
cos \theta=\sqrt{1-(\frac{25}{49})} \\
\\
cos \theta=\sqrt{(\frac{24}{49})} =\frac{\sqrt{24}}{7}\\$

Since $sec \theta=\frac{1}{cos \theta}\\$

So here $sec \theta=\frac{7}{\sqrt{24}}\\$

As we know that

$tan \theta=\frac{sin \theta}{cos \theta}\\
\\ \text{Substitute the values we get}\\
\\
tan \theta=\frac{-5/7}{\frac{\sqrt{24}}{7}}\\
\\
tan \theta=\frac{-5}{\sqrt{24}}\\$

Hence the correct option is C.

5 0

3 years ago

Read 2 more answers