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ICE Princess25 [194]
4 years ago
8

Factor completely 5x^2 + 20x - 60

Mathematics
2 answers:
liubo4ka [24]4 years ago
8 0

Answer:

5(x+6)(x-2)

Step-by-step explanation:

divide by five and you will get this.

5(x^{2} +4x-12)

-12 has factors of -2 and 6 to get the positive 4x. then put it in factored form.

5(x+6)(x-2)

ExtremeBDS [4]4 years ago
7 0

Answer:

x=2, x=-6

Step-by-step explanation:

First, you'll have to factor the left side of the equation.

5(x-2)(x+6)=0

Next, you'll have to set the factors equal to zero.

x-2=0

x+6=0

Finally, you'll have to solve for each factor. For x-2=0, you'll have to add 2 to both sides, and for x+6=0, you'll have to subtract 6 from both sides.

x=2

x=-6

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Answer:

1, 7, 5, 9
7, 1, 9, 5

9, 5, 1, 7

But there are about 10 possible combinations.

Step-by-step explanation:

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3 years ago
What is the summation notation for the series? 200+175+150+125+___+(-300)
ozzi
  21
  E    (225-25n)
n=1
So its D.
5 0
4 years ago
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Under the rectangular survey system, one section is equal to? 36 acres, 64, 360, 640?
daser333 [38]

idk this a really hard problrm

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3 years ago
A tennis player has won 24 out of 36 matches. His sponsor says that he must win 70% of his total number of matches to qualify fo
pashok25 [27]

Answer:

He must win 11 more matches to qualify for the bonus.

Step-by-step explanation:

24/36 * 100 = 67% (to the nearest %) - This is the current percentage of what the Tennis player has won.

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Let's say the Tennis player was playing 100 matches, they would need to win 70 or more to qualify for the bonus. Because the player is playing half this amount of matches, we half the amount of games they have to win...

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Hope that helps!

5 0
3 years ago
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Petes boat can travel 48 miles upstream in 4 hours. The return trip takes 3 hours. Find the speed of the boat in still water and
tankabanditka [31]
So... hmm bear in mind, when the boat goes upstream, it goes against the stream, so, if the boat has speed rate of say "b", and the stream has a rate of "r", then the speed going up is b - r, the boat's rate minus the streams, because the stream is subtracting speed as it goes up

going downstream is a bit different, the stream speed is "added" to boat's
so the boat is really going faster, is going b + r

notice, the distance is the same, upstream as well as downstream
thus   \bf \begin{cases}
b=\textit{rate of the boat}\\
r=\textit{rate of the river}
\end{cases}\qquad thus
\\\\\\

\begin{array}{lccclll}
&distance&rate&time(hrs)\\
&----&----&----\\
upstream&48&b-r&4\\
downstream&48&b+4&3
\end{array}
\\\\\\

\begin{cases}
48=(b-r)(4)\to 48=4b-4r\\\\
\frac{48-4b}{-4}=r\\
--------------\\
48=(b+r)(3)\\
-----------------------------\\\\
thus\\\\
48=\left[ b+\left(\boxed{\frac{48-4b}{-4}}\right) \right] (3)
\end{cases}

solve for "r", to see what the stream's rate is

what about the boat's? well, just plug the value for "r" on either equation and solve for "b"
5 0
4 years ago
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