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Tamiku [17]
3 years ago
14

Which of the following ordered pairs represents the solution to the system of equations below?

Mathematics
1 answer:
expeople1 [14]3 years ago
5 0
<span>-3x + 2y = 2  eq (1)

  7x - 3y = 7    eq (2)

Mutiply eq (1) by 3 and eq (2) by 2:

-9x + 6y = 6

14x - 6y = 14

Add th two new equations:

-9x + 14x = 6 + 14

=> 5x = 20

=> x = 20/5

=> x = 4

Now from eq (1)

-3(4) + 2y = 2

=> 2y = 2 + 12

=> 2y = 14

=> y = 14 / 2

=> y = 7

So the ordered pair is (4,7)

Answer: option B. (4,7)
</span>
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, written in vertex form is

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2 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
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The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

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For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
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3 years ago
Find the measure of YVZ
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Answer:

47 degrees

Step-by-step explanation:

Add all the numbers we know

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133+47=180

47 Your answer. Hope this helped leave a heart or like or comment. :)

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