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3 years ago

Use the distributive property to write and equivalent expression: 6(y+5)

Mathematics

2 answers:

olga55 [171]3 years ago

6 0

Answer:

6y+30

Step-by-step explanation:

1) distributive property is basically multiplying the number outside of the parenthesis with each number/variable inside

6*y+6*5

6y+30

hope this helps

ollegr [7]3 years ago

3 0

Answer:

6y+30

Step-by-step explanation:

(6*y)+(5*6)

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The street sign shown is a regular hexagon with side lengths (4x+30) centimeters. The perimeter of the sign is 798 centimeters.

MrRissso [65]

Answer:

25.75

Step-by-step explanation:

A hexagon has 6 sides so

6(4x + 30) = 798

distribute

24x +180 = 798

take away 180 from both sides

24x = 618

divide 24 both sides to get the variable by itself

X = 25.75

7 0

4 years ago

What is the simplified form of each expression (3/4)^5

iragen [17]

243 over 1024? that's what the cac said

4 0

3 years ago

An = a1 + (n − 1)d Find the 31st term of the sequence -22, -19, -16, -13,...

JulsSmile [24]

Answer:

68.

Step-by-step explanation:

The common difference d = -19 - (-22) = 3

So the 31st term =

a31 = -22 + (31-1)3

= -22 + 90

= 90 - 22

= 68.

4 0

3 years ago

For her presentation on the Wonders of the World, Mary baked a square pyramid-shaped cake as pictured below. The slant height of

miskamm [114]

Answer:

volume = 195.52 in³

Step-by-step explanation:

given data

slant height of the cake = 10 inches

base length = 8 inches

solution

we know that volume pyramid is express as

volume = $\frac{A^2\times h}{3}$ ..............1

here

we use pythagoras for height

hypotenuse² = side1² + side2²

put here value with other side is half of a square side

10² = h² + 4²

solve it we get

h = 9.165 in

so put here value in equation 1 we get

volume = $\frac{8^2\times 9.165}{3}$

volume = 195.52 in³

6 0

3 years ago

Simplify the expression k^14/k^7

VARVARA [1.3K]

$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\
\cfrac{k^{14}}{k^7}\implies k^{14}k^{-7}\implies k^{14-7}\implies k^7$

4 0

4 years ago