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3 years ago

9

Which answer shows a reflection across the x-axis? A B C D

1 answer:

Ivahew [28]3 years ago

7 0

Answer:

C is the correct answer

Step-by-step explanation:

Reflection kinda means like a mirror across the x-axis

in the picture below i labeled the x-axis's and cirlced the answer as well

sorry its not the best drawing but i tried

Hope this helps! Have a nice day! Please consider making me Brainliest

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13 3/5 -b when b = 3

tresset_1 [31]

Answer:

the answer is 10.6

Step-by-step explanation:

5 0

3 years ago

HELP WITH ALL <br> Determine the composite functions of the following set of functions

elixir [45]

QUESTION 1

i) Given $f(x)=5x-2$ and $g(x)=x^2$ .

$(f\circ g)=f(g(x))$

$(f\circ g)=f(x^2)$

We plug in $x^2$ into $f(x)=5x-2$

$(f\circ g)=5x^2-2$

ii) Given $f(x)=5x-2$ and $g(x)=x^2$ .

$(g\circ f)=g(f(x))$

$(g\circ f)=g(5x-2)$

We plug in $5x-2$ into $g(x)=x^2$

$(g\circ f)=(5x-2)^2$

$(g\circ f)=25x^2-10x-10x+4$

$(g\circ f)=25x^2-20x+4$

QUESTION 2

i) Given $g(x)=x^2-4$ and $h(x)=\sqrt{2x+1}$ .

$(h\circ g)=h(g(x))$

$(h\circ g)=h(x^2-4)$

We plug in $x^2-4$ into $h(x)=\sqrt{2x+1}$

$(h\circ g)=\sqrt{2(x^2-4)+1}$

$(h\circ g)=\sqrt{2x^2-8+1}$

$(h\circ g)=\sqrt{2x^2-7}$

ii) Given $g(x)=x^2-4$ and $h(x)=\sqrt{2x+1}$ .

$(g\circ h)=g(h(x))$

$(g\circ h)=g(\sqrt{2x+1})$

We plug in $\sqrt{2x+1$ into $g(x)=x^2-4$

$(g\circ h)=(\sqrt{2x+1})^2-4$

$(g\circ h)=2x+1-4$

$(g\circ h)=2x-3$

QUESTION 3

i) Given $g(x)=x+5$ and $h(x)=\sqrt{x-4}$ .

$(g\circ h)=g(h(x))$

$(g\circ h)=g(\sqrt{x-4})$

We plug in $\sqrt{x-4}$ into $g(x)=x+5$

$(g\circ h)=\sqrt{(x-4)+5}$

ii) Given $g(x)=x+5$ and $h(x)=\sqrt{x-4}$ .

$(g\circ g)=g(g(x))$

$(g\circ g)=g(x+5)$

We plug in $x+5$ into $g(x)=x+5$

$(g\circ g)=(x+5)+5}$

$(g\circ g)=x+10}$

QUESTION 4

The given functions are;

$f(x)=-2x+1$ and $g(x)=-x^2$

$f\circ f=f(f(x))$

$f\circ f=f(-2x+1)$

$f\circ f=-2(-2x+1)+1)$

$f\circ f=4x-2+1)$

$f\circ f=4x-1)$

ii)

$g\circ g=g(g(x))$

$g\circ g=g(-x^2)$

$g\circ g=-(x^2)^2$

$g\circ g=-x^4$

QUESTION 5

$f(x)=5x-2;g(x)=x^2;h(x)=-3x$

$h\circ g\circ f=h\circ (g(f(x))$

$h\circ g\circ f=h\circ (g(5x-2))$

$h\circ g\circ f=h\circ ((5x-2)^2)$

$h\circ g\circ f=h\circ (25x^2-20x+4)$

$h\circ g\circ f=h(25x^2-20x+4)$

$h\circ g\circ f=-3(25x^2-20x+4)$

$h\circ g\circ f=-75x^2+60x-12)$

ii.

$f\circ f\circ g=f\circ (f(g(x))$

$f\circ f\circ g=f\circ (f(x^2)$

$f\circ f\circ g=f\circ (5x^2-2)$

$f\circ f\circ g=f(5x^2-2)$

$f\circ f\circ g=5(5x^2-2)-2$

$f\circ f\circ g=25x^2-10-2$

$f\circ f\circ g=25x^2-12$

7 0

3 years ago

The ratio of pants to shots that John has is 2:3. If John has 8

boyakko [2]

Answer:

12 shirts

Step-by-step explanation:

Since John has 8 pants and 2 x 4 is equal to 8. Then you must multiply the number of shirts by 4 (3 x 4) to give you the number of shirts, which is 12.

Check:

2/3 is equivalent to 8/12

Hope this helps :)

3 0

3 years ago

The table shows the results of a survey in which 10th-grade students were asked how many siblings (brothers and/or sisters) they

lesantik [10]

Answer:

<em>70%</em>

<em></em>

Step-by-step explanation:

Given

Number of Siblings: || 0 || 1 || 2 || 3

Number of Students: || 4 || 18 || 10 || 8

Required

Determine the probability of a student having at least one but not more than 2 siblings

First, we have to determine the total number of 10th grade students

$Total = 4 + 18 + 10 + 8$

$Total = 40$

The probability of a student having at least one but not more than 2 siblings = P(1) + P(2)

Solving for P(1)

P(1) = number of students with 1 sibling / total number of students

From the given parameters, we have that:

Number of students with 1 sibling = 18

So:

$P(1) = \frac{18}{40}$

Solving for P(2)

P(2) = number of students with 2 siblings / total number of students

From the given parameters, we have that:

Number of students with 2 siblings = 10

So:

$P(2) = \frac{10}{40}$

$P(1) + P(2) = \frac{18}{40} + \frac{10}{40}$

Take LCM

$P(1) + P(2) = \frac{18 + 10}{40}$

$P(1) + P(2) = \frac{28}{40}$

Divide numerator and denominator by 4

$P(1) + P(2) = \frac{7}{10}$

$P(1) + P(2) = 0.7$

Convert to percentage

$P(1) + P(2) = 70\%$

<em>Hence, the required probability is 70%</em>

6 0

3 years ago

Explain why there are only three variables in the expression f(x) = a(b)^x + c as it relates to transformations of an exponentia

UkoKoshka [18]

Answer:

Option A.Exponential decay, 55% decrease

we have

This is a exponential function of the form

where a is the initial value

b is the base

b=(1+r)

r is the rate of change

In this problem

a=54

b=0.45

so

0.45=1+r

r=0.45-1

r=-0.55

Convert to percentage

r=-55% ------> is negative because is a exponential decay

7 0

3 years ago