Answer:
40 drops
Approximately 0.166 %
Step-by-step explanation:
It would be easier to work the same units for volume
Since there are 1000 ml in a liter
Original water volume 1.2 L = 1.2 x 1000 = 1200 mLl
The final volume of the acid-water solution = 1.202 L = 1202 mL
So total volume of acid added = 1202-1200 = 2 mL
Each drop of acid is 0.05 mL
Number of drops added = 2/.05 = 40 drops
Percent of acid in acid solution = (Volume of acid added)/(Final volume) x 100 = (2/1202) ≈ 0.00166 x 100 ≈ 0.166 %
Equation 1) x + 6y = 2
Equation 2) 5x + 4y = 36
Multiply all of equation 1 by 5.
1) 5(x + 6y = 2)
Simplify.
1) 5x + 30y = 10
2) 5x + 4y = 36
Subtract equations from one another.
26y = -26
Divide both sides by 26.
y = -1
Plug in -1 for y in the first equation.
x + 6y = 2
x + 6(-1) = 2
Simplify.
x - 6 = 2
Add 6 to both sides.
x = 8
D : (8, -1)
~Hope I helped!~
Answer:
Step-by-step explanation:
-2
Integer is a whole number.