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Varvara68 [4.7K]
3 years ago
10

Select a setting so that each given point will lie within the viewing window.

Mathematics
1 answer:
NemiM [27]3 years ago
6 0

Answer:

The given points are

(-13,3)\\(0,0)\\(-2,-7)

The setting would have a interval or 2 units above and below the minimum and maximum of each coordinate.

The given maxium horizontal coordinate is 0.

The given minimum horizontal coordinate is -13.

The given maximum vertical coordinate is 3.

The given minimum vertical coordinate is -7.

Now, we extend each maximum and minimum value by 2 units to create the setting.

So, the setting is

x_{min}=-15\\x_{max}=2\\ y_{min}=-9\\y_{max}=5

With a scale of 2 units.

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According to the properties of inequality, when should the inequality symbol be reversed when solving a two-step inequality in t
julsineya [31]
Well, 5 is less than 6, but -5 is bigger than -6, so it's when you multiply by a negative number.
6 0
3 years ago
Find a particular solution to y" - y' + 9y = 3 sin 3x
Dima020 [189]

Answer:

cos3x

Step-by-step explanation:

y" - y' + 9y = 3 sin 3x

D^{2}y-Dy+9y=3 sin3x

y=\frac{3 sin 3x}{(D^{2} -D+9}=3 sin 3x

here D^2 will be replaced by  \alpha^2 where \alpha is coefficient of x

y=\frac{3 sin 3x}{-3^{2} -D+9}

y=-3\frac{sin 3x}{D}

y=-3\int\ {sin 3x} \, dx

y=-3\frac{cos3x}{-3}

y=cos3x

hence Particular solution is cos3x

6 0
4 years ago
Tatiaha had $350. She spent$180 on herself and the rest on family.write an equation to express how much she spent on jwr family
valina [46]
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Answer: 350-180=r

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8 0
3 years ago
The figure is made up of a cylinder, a cone, and a half sphere. The radius of the half sphere is 3 inches. What is the volume of
Irina18 [472]

Answer:

The volume of the composite figure is 84π ≅ 263.89 inches³

Step-by-step explanation

- The composite figure consists of :

# Half sphere with radius 3 inches

# Cylinder with radius 3 inches and height 6 inches

# Cone with radius 3 inches and height 4 inches

- The volume of the sphere is 4/3 π r³

∴ The volume of the half sphere = 1/2 × 4/3 π r³ = 2/3 π r³

- The volume of the cylinder is π r² h

- The volume of the cone is 1/3 π r² h

* Now lets solve the problem

- The volume of the half sphere

∵ The radius of the half sphere = 3 inches

∵ The volume of it = 2/3 π r³

∴ The volume = 2/3 × π × (3)³ = 18π inches³

- The volume of the cylinder

∵ The radius of the cylinder = 3 inches

∵ The height of the cylinder = 6 inches

∵ The volume of it = π r² h

∴ Its volume = π × (3)² × 6 = 54π inches³

- The volume of the cone

∵ The radius of the cone = 3 inches

∵ The height of the cone = 4 inches

∵ The volume of it = 1/3 π r² h

∴ Its volume = 1/3 π × (3)² × 4 = 12π inches³

- Add all the volumes to find the volume of the composite figure

∴ The volume = 18π + 54π + 12π = 84π = 263.89 inches³

* The volume of the composite figure is 84π ≅ 263.89 inches³

6 0
3 years ago
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The given lengths are two sides of a right triangle. All three side lengths of the triangle are integers, and together they form a Pythagorean triple. Find the length
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