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max2010maxim [7]
3 years ago
7

HELP. Analyze the diagram below and complete the instructions that follow. Find the exact value of tan 0.

Mathematics
1 answer:
Veronika [31]3 years ago
7 0

Answer:

Using SohCahToa we know it will be opposite over adjacent, opposite being the side across from theta and adjacent being the side next to theta, Using Toa we know it will be opposite over adjacent so the answer will be 6/2sqrt5

If they wants you to simplify more than you cant have a sqrt on the bottom so to fix this you will multiply the top and bottom by sqrt5 leaving you with 6sqrt5/ 2*5 or 6sqrt5/15

hope this helped

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CAN SOMEONE PLEASE ANSWER THE FOLLOWING IT URGENT
emmasim [6.3K]

Answer:

See bolded below.

Step-by-step explanation:

As you said, you only need help with no. 2:

a) Check the attachments for the lines

b) The equations are, respectively:

y = -4x + 1 [intersects parabola at 1 point]

Check:

\begin{bmatrix}y=\left(x-2\right)^2-3\\ y=-4x+1\end{bmatrix}

\begin{bmatrix}-4x+1=\left(x-2\right)^2-3\end{bmatrix}

\begin{bmatrix}-4x+1=x^2-4x+1\end{bmatrix}

x^2=0, x = 0

y=-4\cdot \:0+1 = 1

y=1,\:x=0

The point of intersection would be (0, 1)

y = -4x + 3 [intersects parabola at 2 points]

Check:

\begin{bmatrix}y=\left(x-2\right)^2-3\\ y=-4x+3\end{bmatrix}

Subtract the 2 equations,

y=\left(x-2\right)^2-3\\-\\\underline{y=-4x+3}\\y-y=\left(x-2\right)^2-3-\left(-4x+3\right),\\0=x^2-2\\x = \sqrt{2}, x = - \sqrt{2} \\\\\mathrm{Plug\:the\:solutions\:}x=\sqrt{2},\:x=-\sqrt{2}\mathrm{\:into\:}y=\left(x-2\right)^2-3

\begin{pmatrix}x=\sqrt{2},\:&y=3-4\sqrt{2}\\ x=-\sqrt{2},\:&y=3+4\sqrt{2}\end{pmatrix}

Therefore the points of intersection are (√2, 3-4√2) and (-√2, 3+4√2) respectively

And finally we have the equation y = - 4x. It doesn't intersect the parabola.

c) The y-intercepts of such graphs are all less than or equal to 0.

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Step-by-step explanation:

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Rewriting

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