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galben [10]
4 years ago
12

Can anyone please help me on this Math problem? I am desperate!

Mathematics
1 answer:
salantis [7]4 years ago
8 0
Not sure on the graph, but I have an equation in Standard Form for you. Hope this helps! Message me with any questions!

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Eliminate the parameter:<br> x = 2cost-1 y = 3sint+ 4
adell [148]

Answer:

Hi,

Step-by-step explanation:

\left\{\begin {array} {ccc}x&=&2*cos(t)-1\\y&=&3*sin(t)+4\\\end{array}\right.\\\\\\\left\{\begin {array} {ccc}\dfrac{x+1}{2}&=&cos(t\\\dfrac{y-4}{3}&=&sin(t)\\\end{array}\right.\\\\Squaring\\\\\boxed{(\dfrac{x+1}{2})^2+(\dfrac{y-4}{3})^2&=1}\\

The curve is an ellipse having (-1,4) as center and half-axis (2 and 6)

8 0
2 years ago
If you flip a fair coin 5 times, what is the probability that you will get exactly 3 tails?
Vilka [71]
I agree 3/5! I'm pretty sure, I haven't done this in forever so
3 0
3 years ago
Sarah decides to take her six-year-old son to the circus the price for the child ticket is $4.75 dollars Less in the price for t
kogti [31]
Since the child ticket is y-4.75 (saying y is the adult ticket), we need to solve for y in y-4.75=x. Adding 4.75 to both sides, we get y=x+4.75
3 0
3 years ago
How do u change a value to percentage​
nasty-shy [4]

Answer:

multiple it by 100 and then add the percent sign. These examples convert the numbers 23 and 158 to percents. To convert a number with a decimal into percent, multiply it by 100 and add the percent sign. These examples convert 0.4580; 0.0257; and 0.00458.

Step-by-step explanation:

How to convert fraction to percent

3 = 75%

CAN I PLS HAVE BRAINLIEST

3 0
3 years ago
write equation that has base of 3 stretched vertically by factor of 2/3 reflected in y axis, asymptote of y=2 and passes through
madam [21]

The exponential equation is y = \frac23(3)^{-x+0.74} + 2

<h3>How to determine the equation?</h3>

An exponential function is represented as:

y = b^x

The base is 3.

So, we have:

y = 3^x

It is stretched vertically by 2/3.

So, we have:

y = \frac23(3)^x

When reflected over the y-axis, we have:

y = \frac23(3)^{-x}

An asymptote of y = 2, makes the function becomes

y = \frac23(3)^{-x} + 2

Lastly, it passes through the point (0, 3.5).

So, we have:

y = \frac23(3)^{-x+h} + 2

This gives

3.5 = \frac23(3)^{-0+h} + 2

3.5 = \frac23(3)^{h} + 2

Subtract 2 from both sides

1.5 = \frac23(3)^{h}

Multiply by 3/2

2.25 = (3)^{h}

Take the logarithm of both sides

log(2.25) = h * log(3)

Solve for h

h = 0.74

Substitute h = 0.74 in y = \frac23(3)^{-x+h} + 2

y = \frac23(3)^{-x+0.74} + 2

Hence, the exponential equation is y = \frac23(3)^{-x+0.74} + 2

Read more about exponential equation at

brainly.com/question/23729449

#SPJ1

3 0
2 years ago
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