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Advocard [28]
2 years ago
15

The solution to 4.2x = 19.32 is x = ___. (3 points)

Mathematics
2 answers:
Alla [95]2 years ago
5 0
4.6 because you divide both sides by 4.2
trasher [3.6K]2 years ago
3 0

Answer:

4.6

Step-by-step explanation:


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prisoha [69]

The solution is negative.

8 0
3 years ago
A community activist is gathering data to support an initiative to have a traffic light constructed at a busy intersection near
Arlecino [84]

Answer: 29.6

Step-by-step explanation:

i got it right

8 0
3 years ago
A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

8 0
2 years ago
Q+ad=m solve for d, i need help now please!
Pepsi [2]

Answer:

d =(m-q)/a

Step-by-step explanation:

q+ad=m\\ad = m-q\\\frac{ad}{a} = \frac{m-q}{a} \\\\d = \frac{m-q}{a}

7 0
3 years ago
Read 2 more answers
Jeanna is making holiday cupcakes for her family. She typically makes 2 dozen red velvet and 3 dozen gingerbread spice cake. Sin
valentina_108 [34]

Answer:

15 dozens of cakes

Step-by-step explanation:

It is given that Jeanna is making cupcakes for her family and she normally makes 2 dozens of red velvet cakes and 3 dozens of gingerbread spice cakes. But as everybody is staying at home, Jeanna wants to increase the standard amount by 3 for enough cakes.

So,

2 dozens of velvet cakes, i.e.

2 x 12 = 24 red velvet cakes

Increasing this amount by 3 times will give us 24 x 3 = 72 red velvet cakes.

Similarly,

3 dozens of gingerbread spice cakes, i.e.

3 x 12 = 36 gingerbread spice cakes

Increasing this amount by 3 times will give us 36 x 3 = 108 gingerbread spice cakes.

Therefore the total number of cakes is = 72 + 108

                                                                 = 180 cakes.

We know 1 dozen = 12

Therefore dividing 180 cakes by 12, we get

$=\frac{180}{12}$

= 15 dozen cakes.

Therefore, now Jeanna will have to make 15 dozens of cupcakes for all.

5 0
3 years ago
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