21.6k + 11.8
I believe is the answer good luck!
we know that
The measurement of the exterior angle is the semi-difference of the arcs which comprises
In this problem
∠FGH is the exterior angle
∠FGH=
∠FGH=
-----> equation A

--------> equation B
Substitute equation B in equation A
![100\°=(arc\ FEH-[360\°-arc\ FEH])](https://tex.z-dn.net/?f=100%5C%C2%B0%3D%28arc%5C%20FEH-%5B360%5C%C2%B0-arc%5C%20FEH%5D%29)



therefore
<u>The answer is</u>
The measure of arc FEH is equal to 
Answer:
$3.41
Step-by-step explanation:
262.94 + 83.65 = 346.59
350.00 - 346.59 = 3.41
R - (12÷r)+2
I think that thats the answer
Sin D= opp./hyp. = 35/37
cos D= adj./hyp. = 12/37
tan D= opp./ adj. = 35/12