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ddd [48]
3 years ago
14

Please help 6 points​

Mathematics
2 answers:
USPshnik [31]3 years ago
6 0

its c

Step-by-step explanation:

92x7=644

Your Welcome

Marrrta [24]3 years ago
3 0

Answer: B

Step-by-step explanation: 644 - 92 = 552

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Use the method pemdas and you get x=28
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3 years ago
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Find the length of one edge of the cube. <br> Edge length = Answer inches
ycow [4]

Volume

V = l³

length (inverse formula)

l = ∛512

l = 8 in (your answer)

5 0
3 years ago
(x-1)^2+(2-x)^2-3(x-5)*(x-5)
Natali5045456 [20]

Answer:

-x^2+24x-70

Step-by-step explanation:

(x-1)^2+(2-x)^2-3(x-5)*(x-5)\\=> (x - 1)^2 + (2 - x)^2 - 3(x - 5)^2\\=> x^2 - 2x + 1 + 4 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 2x + 5 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 6x + 5 + x^2 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x^2 - 10x + 25)\\=> 2x^2 - 6x+5  - 3x^2+30x-75\\=> -x^2 - 6x + 5 + 30x - 75\\=> -x^2 + 24x + 5-75\\=> -x^2+24x-70

Formula used =

(a-b)^2 = a^2+ 2ab + b^2

8 0
2 years ago
Costs of homes can be very different in different parts of the United States. a. A 450-square-foot apartment in New York City co
VLD [36.1K]

Answer:

The cost of homes per square foot differs in different part of the United states. The cost of homes per square foot is gotten by using the formula:

cost of homes per square foot = Cost of apartment / area of apartment

1) Cost of apartment = $540000, area of apartment = 450 ft²

cost of homes per square foot = Cost of apartment / area of apartment = $540000/ 450 ft² = $1200 / ft²

2) cost of homes per square foot = $110/ ft²,  area of apartment = 2100 ft²

cost of homes per square foot = Cost of apartment / area of apartment

$110 / ft² = Cost of apartment / 2100 ft²

Cost of apartment = $110 / ft² × 2100 ft² = $231000

Step-by-step explanation:

Hope this helps plz mark brainiest  

5 0
2 years ago
Read 2 more answers
According to a survey, high school girls average 100 text messages daily (The Boston Globe, April 21, 2010). Assume the populati
Ghella [55]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: number of daily text messages a high school girl sends.

This variable has a population standard deviation of 20 text messages.

A sample of 50 high school girls is taken.

The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;δ²/n)

This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:

Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)

a.

P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836

b.

P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)

P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328

I hope you have a SUPER day!

3 0
2 years ago
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