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2 years ago

NEED HELP ASAP ON THIS QUESTION

Mathematics

2 answers:

andrew11 [14]2 years ago

7 0

Answer:

None of these answers are correct.

Step-by-step explanation:

If a²+b²=c², then 7²+5²=c², then if you solve for c this equals about 8. This is none of the answers mentioned which is 8. Also, a good thing to remember is that the hypotenuse is always larger than the two side lengths. So, since the answer is 8 then it is none of the answers.

qwelly [4]2 years ago

7 0

None of them / last choice

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iren2701 [21]

The function that represents surviving people are X = 2m - d

Given that there are m married couples and d of the 2m of these couples have died, the total people that remain is expressed as:

Total people remaining = Total married couple - those that died

Total married couple = 2m

Total people that died = d

Taking the difference to get the remaining people;

Total people remaining = 2m - d

Hence the function that represents surviving people are X = 2m - d

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3 years ago

You order a new pair of running shoes from a website that offers free shipping on orders of $75 or more. Your shoes cost $69.95.

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3 years ago

Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 1

Yuri [45]

Answer:

90% confidence interval for the population mean test score is [95.40 , 106.59]

Step-by-step explanation:

We are given that the population mean score for mathematics test is 115. It is known that the population standard deviation of test scores is 17.

Also, a random sample of 25 students take the exam. The mean score for this group is 101.

The, pivotal quantity for 90% confidence interval for the population mean test score is given by;

P.Q. = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean = 101

$\sigma$ = population standard deviation

n = sample size = 25

So, 90% confidence interval for the population mean test score, $\mu$ is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.6449) = 0.90

P(-1.6449 * $\frac{\sigma}{\sqrt{n} }$ < ${Xbar-\mu}$ < 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

P(X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ < $\mu$ < X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

90% confidence interval for $\mu$ = [ X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ , X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ]

= [ 101 - 1.6449 * $\frac{17}{\sqrt{25} }$ , 10 + 1.6449 * $\frac{17}{\sqrt{25} }$ ]

= [95.40 , 106.59]

Therefore, 90% confidence interval for the population mean test score is [95.40 , 106.59] .

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3 years ago