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love history [14]
3 years ago
5

Which statement is true regarding the two shaded sectors of circle O? Explain.

Mathematics
2 answers:
ZanzabumX [31]3 years ago
6 0

Answer: C

Step-by-step explanation:

Just did it

Bogdan [553]3 years ago
6 0

Answer:

(C) The area of sector AOB is equal to the area of sector DOC because the central angle measures are equal.

Step-by-step explanation:

just did it on edge

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Taking a test!!! I need help on it pleaseee!!!
ivann1987 [24]

Answer:

The first one is right the rest of them is not right correct

Step-by-step explanation:

8 0
3 years ago
What are the solutions to the equation |x – 10| – 4 = 2x?
Yuliya22 [10]

|x – 10| – 4 = 2x

x - 10 - 4 = 2x

x - 14 = 2x

x - 2x = 14

-x = 14

x = -14

7 0
3 years ago
If DM=45, what is the value of r?
amm1812

Answer:

15

Step-by-step explanation:

6 0
3 years ago
Jason states that Triangle A B C is congruent to triangle R S T. Kelley states that Triangle A B C is congruent to triangle T S
Brilliant_brown [7]

Answer:

The correct option is;

Jason's statement is correct. RST is the same orientation, shape, and size as ABC

Step-by-step explanation:

Here we have

ABC = (2, 1), (3, 3), (4, 1)

RST = (-4, -2), (-3, 0), (-2, -2)

Therefore the length of the sides are as follows

AB = \sqrt{(2-3)^2+(1-3)^2} = \sqrt{5}

AC = \sqrt{(2-4)^2+(1-1)^2} =2

BC = \sqrt{(3-4)^2+(3-1)^2} = \sqrt{5}

For triangle SRT we have

RS = \sqrt{(-4-(-3))^2+(-2-0)^2} = \sqrt{5}

RT = \sqrt{(-4-(-2))^2+(-2-(-2))^2} = 2

ST = \sqrt{(-3-(-2))^2+(0-(-2))^2} = \sqrt{5}

Therefore their dimensions are equal

However the side with length 2  occurs between (2, 1) and (4, 1) in triangle ABC and between (-4, -2) and (-2, -2) in triangle RST

That is Jason's statement is correct. RST is the same orientation, shape, and size as ABC.

4 0
3 years ago
Read 2 more answers
What is the value of hin the figure below? In this diagram, ABAD ~ ACBD.
VashaNatasha [74]

Answer:

  F.  8

Step-by-step explanation:

The ratio of the long side to the short side is the same in similar triangles. The long side of triangle BAD is AD, which has length 20-4 = 16.

  BD/DE = AD/BD

  h/4 = 16/h

  h^2 = 64 . . . . . . . multiply by 4h

  h = 8 . . . . . . . . . . take the square root (matches selection F)

_____

<em>Comment on this geometry</em>

BD = √(AD·DC) is called the "geometric mean" of the segments AD and DC. This geometry has some other geometric mean relationships as well:

BC = √(AC·DC)

BA = √(AC·AD)

8 0
3 years ago
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