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dimaraw [331]
4 years ago
14

Kendra is flying a kite. The angle of elevation from Kendra to the kite is 56Á. If the distance from KendraÍs hands to the kite

is 50 feet, what is the horizontal distance from Kendra to the point directly under the kite (point B)? Round your answer to the nearest tenth.
Mathematics
1 answer:
Oliga [24]4 years ago
3 0
<span>Assuming that the string of the kite does not sag. It then serves as the hypotenuse of the right triangle. The horizontal distance is the length of the base of the triangle. The horizontal distance can the be calculated using trigonometry: h = 50 cos(56 deg) = 28.0 ft.
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Those are my choices pls tell me which one would fit this problem!! <br>THERES A PIC ATTACHED
denis23 [38]

Answer: Opens up, has a minimum

Step-by-step explanation:

If the x^2 term is positive the parabola opens up, if it is negative it opens down. Minimum always goes with up, maximum with down

7 0
3 years ago
Jennifer has a taco stand.she found that her daily costs can be modeled by C(x)=x^2-40x+610. if she wants to keep her daily cost
polet [3.4K]
Let's focus on the given equation. The C represents the cost, while the x must be the number of tacos, which is what we're solving for. Since we're given the boundary that C must be 300, then the solution would be:

300 = x² - 40x + 610
x² - 40x + 310 = 0

Apply the quadratic formula where a = 1, b = -40 and c = 310. The roots of x are:
x = 29.49≈30
x = 10.51≈11

<em>Thus, she needs to sell either 30 or 11 tacos.</em>

4 0
4 years ago
A study indicates that 37% of students have laptops. You randomly sample 30 students. Find the mean and the standard deviation o
Brilliant_brown [7]

Answer:

The mean and the standard deviation of the number of students with laptops are 1.11 and 0.836 respectively.

Step-by-step explanation:

Let <em>X</em> = number of students who have laptops.

The probability of a student having a laptop is, P (X) = <em>p</em> = 0.37.

A random sample of <em>n</em> = 30 students is selected.

The event of a student having a laptop is independent of the other students.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The mean and standard deviation of a binomial random variable <em>X</em> are:

\mu=np\\\sigma=\sqrt{np(1-p)}

Compute the mean of the random variable <em>X</em> as follows:

\mu=np=30\times0.37=1.11

The mean of the random variable <em>X</em> is 1.11.

Compute the standard deviation of the random variable <em>X</em> as follows:

\sigma=\sqrt{np(1-p)}=\sqrt{30\times0.37\times(1-0.37)}=\sqrt{0.6993}=0.836

The standard deviation of the random variable <em>X</em> is 0.836.

5 0
3 years ago
Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are
Kruka [31]

Answer:

Step-by-step explanation:

The formula for determining the confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

Where

x1 = sample mean of type A paint

x2 = sample mean of type B paint

s1 = sample standard deviation type A paint

s2 = sample standard for type B paint

n1 = number of samples of type A paint

n2 = number of samples of type B paint

From the information given,

x1 = 75.7

s1 = 4.5

n1 = 11

x2 = 64.3

s2 = 5.1

n2 = 9

x1 - x2 = 75.7 - 64.3 = 11.4

√(s1²/n1 + s2²/n2) = √(4.5²/11 + 5.1²/9) = √4.709

Degree of freedom = (n1 - 1) + (n2 - 1)

df = (11 - 1) + (9 - 1) = 18

For the 98% confidence interval, the z score from the t distribution table is 2.552

Margin of error = 2.552√4.709 = 5.55

The upper boundary for the confidence interval is

11.4 + 5.55 = 16.95 hours

The lower boundary for the confidence interval is

11.4 - 5.55 = 5.85 hours

The correct option is

B. 5.85 hrs < μ1 - μ2 < 16.95 hrs

4 0
3 years ago
a rectangular sign has a length of 3 and 1/2 ft and width of 1 and 1/8 ft will the area of the sign be greater or less than 3 an
svetoff [14.1K]

Answer:

The area is 3.9375 cubic ft, so yes, the area will greater than 3 and 1/2 ft.

Hope this helps:)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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