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2 years ago

AB is parallel to DC.

Mathematics

1 answer:

AlekseyPX2 years ago

4 0

Answer:

Step-by-step explanation:

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Nadia is a stockbroker. She earns 11% commission each week. Last week, she sold 7,200 worth of stocks. How much did she make las

elena55 [62]

Answer:

She made 792 dollars that week. I'm assuming it is just asking for the yearly commission she made. That would be 41,184 dollars a year.

Step-by-step explanation:

7200 x 0.11 = 792 Weekly

52 Weeks in a year

792 x 52 = 41184 Yearly (if that's what it's asking for)

6 0

3 years ago

This is the answer right?

dalvyx [7]

No, the question is stating the product of a number (the variable n represents the number) and 10 is 142. In other words, 10 times another number is 142. Hence, the answer would be A.

5 0

3 years ago

A sequence is constructed according to the following rule: its first term is 7, and each next term is one more than the sum of t

Iteru [2.4K]

Answer:

Step-by-step explanation:

According to the described rule, we have

$a_1=7\\ \\a_1^2=7^2=49\Rightarrow a_2=4+9+1=14\\ \\a_2^2=14^2=196\Rightarrow a_3=1+9+6+1=17\\ \\a_3^2=17^2=289\Rightarrow a_4=2+8+9+1=20\\ \\a_4^2=20^2=400\Rightarrow a_5=4+0+0+1=5\\ \\a_5^2=5^2=25\Rightarrow a_6=2+5+1=8\\ \\a_6^2=8^2=64\Rightarrow a_7=6+4+1=11\\ \\a_7^2=11^2=121\Rightarrow a_8=1+2+1+1=5\\ \\\text{and so on...}$

We can see the pattern

$a_5=a_8=a_{11}=a_{14}=...=5\\ \\a_6=a_9=a_{12}=a_{15}=...=8\\ \\a_7=a_{10}=a_{13}=a_{16}=...=11$

In other words, for all $k\ge 2$

$a_{3k-1}=5\\ \\a_{3k}=8\\ \\a_{3k+1}=11$

Now,

$a_{2018}=a_{3\cdot 673-1}=5$

7 0

3 years ago

Write the expression as either the sine, cosine, or tangent of a single angle. tan5x - tan2y / 1 + tan5x tan2y

Kryger [21]

$\bf \textit{Sum and Difference Identities}
\\\\
tan(\alpha + \beta) = \cfrac{tan(\alpha)+ tan(\beta)}{1- tan(\alpha)tan(\beta)}
\qquad
tan(\alpha - \beta) = \cfrac{tan(\alpha)- tan(\beta)}{1+ tan(\alpha)tan(\beta)}\\\\
-------------------------------\\\\
\cfrac{tan(5x)-tan(2y)}{1+tan(5x)tan(2y)}\implies tan(5x-2y)$

6 0

3 years ago

If a = 5^x, b = 5^y and a^y×b^x = 25 then prove that: xy =1

avanturin [10]

$a = {5}^{x} \\ b = {5}^{y} \\ {a}^{y} \times {b}^{y} = 25 \\ prove \: ( {5}^{x} )^{y} \times ( {5}^{y} ) ^{x} = 25 \\ {5}^{xy} \times {5}^{yx} = {5}^{2} \\ {5 }^{xy + yx} = 5^{2} \\ 5^{2xy} = {5}^{2} \\ is \: \: 2xy = 2 \\ xy = \frac{2}{2} \\ xy = 1$

3 0

3 years ago