All categories

3 years ago

X - 35 > 15 i need answer IMEDIATLEY

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

6 0

I'm assuming you want us to solve this inequality for x, since the question wasn't too clear on that.

$x - 35 > 15$

Add 35 to both sides to remove the "-35" on the left side so we can isolate the x

$x-35+35>15+35$

$x>50$

The solution to this inequality is x>50. Let me know if you need any clarifications, thanks!

~ Padoru

You might be interested in

1/4 divided by 3 = ___

Yuki888 [10]

Answer:

$\frac{1}{4} \div 3 = \frac{\frac{1}{4} }{3} = \frac{1}{12}$

6 0

3 years ago

Read 2 more answers

Can 4x-2y=12x+2y=8 be solved by adding one of the original equations to the other

nydimaria [60]

Answer:

No you can't add problems together, but you can use elimnation

Step-by-step explanation:

6 0

3 years ago

Find solution r+9-6r=28

IgorC [24]

Answer:

hope this is correct

7 0

3 years ago

Read 2 more answers

Simon must maintain an average grade of 80% or better in his math class to be eligible to play sports.His math grade so far are

Sophie [7]

Answer:

Let x be the percentage score he got in fifth test,

According to the question,

His score in first, second, third and fourth test are 80%, 84%, 76% and 77% respectively,

Thus, the average of his total score in the five test,

= $\frac{80+84+76+77+x}{5}$

But, Again according to the question,

The average of the five grades as greater than or equal to 80%

That is,

$\frac{80+84+76+77+x}{5}\geq 80$

⇒ $\frac{317+x}{5}\geq 80$

⇒ $317 + x \geq 400$

⇒ $x\geq 83$

Thus, the least score he can get in the fifth test is 83.

3 0

3 years ago

a person on Mars only weighs 38% of their weight on Earth if Carla weighs 78 pounds on Earth how much would you weigh on Mars to

Bumek [7]

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

❖ Carla would weigh 30 pounds.

38/100 x 78 = 29.64

29.64 rounded to the nearest pound is 30.

So, Carla would weigh 30 pounds.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

8 0

3 years ago

Read 2 more answers