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Artyom0805 [142]
3 years ago
7

5k + 2 items for a total cost of 35k 2 + 29k + 6.

Mathematics
1 answer:
Elena L [17]3 years ago
7 0
69,010 is the total cost of ???
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16.
Dmitry_Shevchenko [17]
Chaliye apni maa chudaiye
4 0
3 years ago
In your own words, describe the steps you take to round a decimal.
lys-0071 [83]
First find which value you would like to round up or down

second if the number is less than five round down, if the number is more than five round up

hope this helps
4 0
3 years ago
Read 2 more answers
I need details please
m_a_m_a [10]
Ok, first you need to read a - g and mark down the information you know. Also, this continuous function can look pretty much like anything long as it has the a - g constraints/rule. 

A) We know the domain(x values) is between -10 to infinity
(-10,-9,-8,-7,-6,-5,-4,-3-,2,-1,0,1,2,3,4,5,6,7,8,9,10, to ---------> infinity)
B) We know the range(y values) is between -6 to infinity
(-6,-5,-4,-3-,2,-1,01,2,3,4,5,6,7,8,9,10, to ---------> infinity) 

C) Next we know f(0) = f(4) = 0
So we know when x = 0  that f(0) = 0 or we can say  y = 0. We also know when f(4) = 0 so when x = 4 y = 0. So we have two points (0,0) and (4,0) that our function will be on so plot the two points (0,0) (4,0)

D) It tells us that f(x) (y) is increasing between the x values (-10,-6)  or (-2,2) or (4, to infinity)

E) It tells us that f(x) (y) is decreasing between the x values (-6,-2) or between (2,4)

F) Tells us that f(x) (y) is greater than or equal to between the x values of [-8,-4] or between the x values [0, to infinity) so this lets us know our drawing is going to be above or equal to 0 when we are in the values [-8,-4] or [0, to infinity)

G) Tells us that f(x) (y) is less than 0 when the function / drawing is between the x values of (-10, -8) or (-4,0)  

The picture is what the function could look like. It can be different but needs to following the rules that are given 




3 0
3 years ago
Please help me in this one!!
olga2289 [7]
A^3
a to the power of three
6 0
3 years ago
Read 2 more answers
A scientist has 100 milligrams of a radioactive element. The amount of radioactive element remaining after t days can be determi
grandymaker [24]
The mass of the first shipment at time t is
m_{1}=100( \frac{1}{2} )^{ \frac{t}{10}}

The mass of the second shipment at time t is
m_{2}=100( \frac{1}{2} )^{ \frac{t-3}{10} }

At time t, the ratio of m₁ to m₂ is
\frac{m_{1}}{m_{2}} = \frac{100}{100}. \frac{(1/2)^{t/10}}{(1/2)^{(t-3)/10}} \\ =  \frac{(1/2)^{t/10}}{(1/2)^{t/10}}. \frac{1}{(1/2)^{-3/10}} \\ = (1/2)^{3/10} \\ = 0.8123

Therefore as a percentage,
\frac{m_{1}}{m_{2}} =100*0.8123 = 81.23 \%

Answer: B. 81.2%

4 0
4 years ago
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