Answer:
Groove
Explanation:
There is not much to explain
Answer:
<em>The ROE in plain terms is called the return on equity (ROE) is a measure of inflow of profit in business in relation to the equity, also known as assets net worth or assets of liabilities ROE is a method of how l company generate earnings through investment </em>
Explanation:
<em>The ROE in plain terms is called the return on equity (ROE) is a measure of inflow of profit in business in relation to the equity, also known as assets net worth or assets of liabilities ROE is a method of how l company generate earnings through investment </em>
<em>The ROE range number can be of any value or percentage example 15% upwards</em>
<em>The type of person or position with roles to play are usually a professional, such as an accountant, bookkeeper, or payroll processor, who completes ROEs on behalf of your clients in the organisation.</em>
You must first locate the queries group on the create tab.
This tab contains the commands used to create queries. MS Access will switch
itself to the query design view. A show table dialog box will appear and you will
be able to select a table you would want to run a query on.
Answer:
Written in C++
void number(int n){
if(n%2 == 0)
cout<<2 * n;
else
cout<<5 * n;
}
Explanation:
The programming language is not stated.
However, I answered using C++
This line defines the function as void
void number(int n){
This line checks if the number is even
if(n%2 == 0)
If yes, it doubles the number and prints the output
cout<<2 * n;
If otherwise,
else
It multiplies the number by 5 and prints the output
cout<<5 * n;
}
To call the function from main, use:
number(n);
Note than n must be declared as integer
See attachment
Answer:
#include <iostream>
#include <array>
using namespace std;
bool isPalindrome(string str)
{
int length = str.length();
for (int i = 0; i < length / 2; i++)
if (toupper(str[i]) != toupper(str[length - 1 - i]))
return false;
return true;
}
int main()
{
array<string, 6> tests = { "madam", "abba", "22", "67876", "444244", "trymEuemYRT" };
for (auto test : tests) {
cout << test << " is " << (isPalindrome(test) ? "" : "NOT ") << "a palindrome.\n";
}
}
Explanation:
The toupper() addition forces characters to uppercase, thereby making the comparison case insensitive.