All categories

2 years ago

Solve for x: 6/x = 4/8 A)10 B)12 C)24 D)48

Mathematics

1 answer:

Ksenya-84 [330]2 years ago

7 0

Answer:

B)12

Step-by-step explanation:

6/x = 4/8

6/x = 1/2

6 * 2 = 1 * x

12 = x

x = 12

You might be interested in

Verify identity: <br><br> (sec(x)-csc(x))/(sec(x)+csc(x))=(tan(x)-1)/(tan(x)+1)

Nikitich [7]

So hmmm let's do the left-hand-side first

$\bf \cfrac{sec(x)-csc(x)}{sec(x)+csc(x)}\implies \cfrac{\frac{1}{cos(x)}-\frac{1}{sin(x)}}{\frac{1}{cos(x)}+\frac{1}{sin(x)}}\implies 
\cfrac{\frac{sin(x)-cos(x)}{cos(x)sin(x)}}{\frac{sin(x)+cos(x)}{cos(x)sin(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)sin(x)}\cdot \cfrac{cos(x)sin(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

now, let's do the right-hand-side then

$\bf \cfrac{tan(x)-1}{tan(x)+1}\implies \cfrac{\frac{sin(x)}{cos(x)}-1}{\frac{sin(x)}{cos(x)}+1}\implies \cfrac{\frac{sin(x)-cos(x)}{cos(x)}}{\frac{sin(x)+cos(x)}{cos(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)}\cdot \cfrac{cos(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

7 0

2 years ago

12/11k÷4/3k<br><br>simplify the fraction

Nonamiya [84]

Answer:

9/11

Step-by-step explanation:

12/11k÷4/3k

Copy dot flip

12/11k* 3k/4

36k / 44k

Divide the top and bottom by 4k

9/11

3 0

2 years ago

Read 2 more answers

Ok this is like not helpful but i did this i past my math class

Tema [17]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Solve the following equation using the quadratic formula: 12x^2+x-1=0

german

Answer:

-1/3 1/4 answers b

Step-by-step explanation:

3 0

2 years ago

State the hypotenuse, opposite and

UkoKoshka [18]

Answer:

hypotenuse:2 (AB)

adjacent side: 1 (AD)

opposite side:√3(BD)

Step-by-step explanation:

-->AB is hypotenuse cuz it's opposite to right angle (90°)

-->AD is adjacent,cuz it's adjacent to reference angle(60°)

-->BD is opposite side,cuz it's opposite to the reference angle(60°)

✌️:)

4 0

2 years ago