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Diano4ka-milaya [45]
3 years ago
8

A heptagon can be divided into how many triangles by drawing all of the diagonals from one vertex?

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
7 0
That would be   5 triangles.  
Eddi Din [679]3 years ago
5 0

Answer:

The answer is 5 triangles.

Step-by-step explanation:

A heptagon is a seven sided polygon.

So, the number of triangles that can be drawn from 1 vertex in any polygon with n sides, is given by : n-2.

Therefore, in a heptagon, we can draw 7-2=5 triangles.

The sum of the interior angles of a heptagon is 900 degrees. We can check this by taking the total interior angle sum of 5 triangles.

Sum of internal angle of triangles is = 180 degrees.

So, sum of 5 triangles will be = 180\times5=900 degrees.

This proves, a heptagon can have 5 triangles.

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Which of the following equations matches the function shown above?
yanalaym [24]

Answer:

C=y=sin1/2x

Step-by-step explanation:

As given in the graph:

Amplitude= 1

period=2π

Finding function of sin that have period of 4π and amplitude 1

A: y=1/2sinx

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1/2

b=1

c=0

d=0

Amplitude=|a|

                =1/2

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B: y=sin2x

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1

b=2

c=0

d=0

Amplitude=|a|

                =1

Period= 2π/2

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Using the formula  asin(bx-c)+d to find the amplitude and period

a=1

b=1/2

c=0

d=0

Amplitude=|a|

                =1

Period= 2π/1/2

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D: y=sin1/4x

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1

b=1/4

c=0

d=0

Amplitude=|a|

                =1

Period= 2π/1/4

         =8π

Hence only c: y=sin1/2x has period of 2π and amplitude 1

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3 years ago
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