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4 years ago

X/3 +4 < 6x/3 <x. 6

Mathematics

2 answers:

lisabon 2012 [21]4 years ago

8 0

Answer:

x < 6

u mean like this

Step-by-step explanation:

x/3 + 4 <6

x/3 + 12/3 <18/3

x + 12 < 18

x < 6

so this equation make sense when x<6

Done :))

Ahat [919]4 years ago

3 0

Hola, qué tal tu día

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Negative

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2 years ago

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Find the slope and y-intercept and tell me if its proportional or non-proportional.

weqwewe [10]

Answer:

Slope: 6

Y-intercept: 0

Proportional

Step-by-step explanation:

The equation for this table is y = 6x + 0 or just y = 6x.

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y-value slope (x-value) y-intercept

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3 years ago

In a shipment of 20 packages, 7 packages are damaged. The packages are randomly inspected, one at a time, without replacement, u

horsena [70]

Answer:

$\large\boxed{\large\boxed{0.119}}$

Explanation:

You need to find the probability that exactly three of the first 11 inspected packages are damaged and the fourth is damaged too.

1. Start with the first 11 inspected packages:

a) The number of combinations in which 11 packages can be taken from the 20 available packages is given by the combinatory formula:

$C(m,n)=\dfrac{m!}{m!(m-n)!}$

$C(20,11)=\dfrac{20!}{11!\cdot(20-11)!}$

b) The number of combinations in which 3 damaged packages can be chossen from 7 damaged packages is:

$C(7,3)=\dfrac{7!}{3!\cdot(7-3)!}$

c) The number of cominations in which 8 good packages can be choosen from 13 good pacakes is:

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d) The number of cominations in which 3 damaged packages and 8 good packages are chosen in the first 11 selections is:

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Subsituting:

$\dfrac{\dfrac{7!}{3!\cdot(7-3)!}\times \dfrac{13!}{8!\cdot(13-8)!}}{\dfrac{20!}{11!\cdot(20-11)!}}$

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2. The 12th package

The probability 12th package is damaged too is 7 - 3 = 4, out of 20 - 11 = 9:

3. Finally

The probability that exactly 12 packages are inspected to find exactly 4 damaged packages is the product of the two calculated probabilities:

$0.26818885\times 4/9=0.119$

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4 years ago

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3 years ago

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Answer:

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X/3 +4 < 6x/3 <x. 6​

X/3 +4 < 6x/3 <x. 6