Answer:
I'm so sorry!!! I don't understand how you are supposed to do this problem... I hope someone can help you out. Have a good day
Step-by-step explanation:
Super sorry
400,000,000 + 30,000,000 + 200,000 + 90,000 +100
Answer:
The 90% confidence interval for the mean time required by all college graduates is between 5.36 years and 5.44 years.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so
Now, find the margin of error M as such
In which
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 5.4 - 0.04 = 5.36 years.
The upper end of the interval is the sample mean added to M. So it is 5.4 + 0.04 = 5.44 years.
The 90% confidence interval for the mean time required by all college graduates is between 5.36 years and 5.44 years.
I took out the greatest common factor, which is y^2 and factored from there
You’ll end up with y^2(y+2)(y+8)
Here’s my work :)
Answer:
can l
Step-by-step explanation:
can l? can l? can l~